The direction vector of the line
L: x=1+t, y=4t, z=2-3t
is <1,4,-3>
which is also the required normal vector of the plane.
Since the plane passes through point (-5,9,10), the required plane is :
Π 1(x-(-5)+4(y-9)-3(z-10)=0
=>
Π x+4y-3z=1
<span>0, (4) = 4/9 <span>L circle = 2πR </span><span>L circle = 2 · π · 4/9 </span><span>L circle = 8π / 9 cm
</span></span>L = 2 * pi * R
<span>L = 2 * pi * 0. (4) cm = 0. (8) pi cm</span>
Answer:
Step-by-step explanation:
Given
See attachment
Required
The solution
The solution is at the point where the two lines meet.
The lines meet at:
and 
So, the solution is:
