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4 years ago

MATH HELP 50 POINTS

Mathematics

2 answers:

Free_Kalibri [48]4 years ago

7 0

We know that
the law of cosines establish
c²=a²+b²-2*a*b*cos C------> cos C=[a²+b²-c²]/[2*a*b]

in this problem
a=11 units
b=11 units
c=14 units
C=angle A

cos C=[11²+11²-14²]/[2*11*11]-----> cos C=0.19008
C=arc cos (0.19008)------> C=79.04°

the answer is
the measure of angle A is 79°

Svetllana [295]4 years ago

6 0

Your answer is 79 degrees :D

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The two polygons are similar.Find the length of x

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x = 9.2

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3 years ago

Second Time Asking This:

sattari [20]

128 ÷3=42.66

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3 years ago

Which triangle drfined by the given points on the coordinate plane is similar to the triangle illustrated?

Harrizon [31]

Answer:D.) (-1, 1), (-1, 5), (-7, 1)

Step-by-step explanation:The length of the horizontal segment of the triangle graphed is 3. The length of the vertical segment of the triangle graphed is 2. Using the Pythagorean theorem, this makes the length of the missing side

2²+3²=c²

4+9 = c²

13=c²

√13 = c

This makes our side lengths 2, 3, and √13.

For choice A our vertices are (-1, 1), (-1, 4), (-6, 1).

This makes the length of the horizontal segment 5 and the length of the vertical segment 3. This makes the missing side length

5²+3²=c²

25+9=c²

34=c²

√34 = c

This is not proportional to the triangle drawn, so it is not similar.

The vertices of the triangle in option B are (-1, 1), (-1, 5), and (-6, 1). This makes the horizontal segment 5 units long and the vertical segment 4 units long. This makes the missing side length

4²+5²=c²

16+25=c²

41=c²

√41=c

These are not proportional to the triangle drawn, so the triangles are not similar.

The vertices of the triangle in choice C are (-1, 1), (-1, 4) and (-7, 1). This makes the length of the horizontal segment 6 and the length of the vertical segment 3. This makes the missing side length

3²+6²=c²

9+36=c²

45=c²

√45=c

3√5=c

These sides are not proportional to the sides of the triangle drawn, so the triangles are not similar.

The vertices of the triangle in choice D are (-1, 1), (-1, 5) and (-7, 1). This makes the length of the horizontal segment 6 and the length of the vertical segment 4. This makes the missing side length

6²+4²=c²

36+16=c²

52=c²

√52=c²

2√13=c

These sides are all twice as long as the sides of the triangle drawn; this means the triangles are similar.

4 0

3 years ago

I’ll give you brainliest for the first person with an answer

raketka [301]

Answer:

1296mm^2

Step-by-step explanation:

Surface Area of the Rectangular Prism to the left on top of the box:

Area of square = lw, 9mm * 9mm = 81mm, then multiply by 2 because 2 of the squares are a part of the surface, giving 162mm^2

Area of a rectangle =lw, 9mm * 9mm = 81mm, then multiply by 2 again, because 2 rectangles are a part of the surface, giving 162mm^2

So, the total surface area of the rectangular prism to the left on top, is 324mm^2

Surface Area of the Triangular Prism:

Area of a triangle: 1/2bh, and our base length would be 12, because we have to subtract 9 from 21 since the base length of the triangle isn't stated. Anyways, A = 1/2bh, so A = 1/2(12)(9) = 54mm^2, but multiply by two, so we get 108mm^2.

Area of the rectangle: lw, so 15mm * 9mm = 135mm^2

So, the total surface area of the triangular prism is 243mm^2

Surface Area of the Rectangular Prism at the bottom:

Area of the long rectangles in front = lw, 21mm * 9mm = 189mm^2, multiply by 2, 378mm^2

Area of the rectangles to the side = lw, 9mm * 9mm = 81mm^2, multiply by 2, 162mm^2

Area of the rectangle at the very bottom = lw, 21mm * 9mm = 189mm^2

So, the total surface area of the rectangular prism at the bottom is 729mm^2

Add all the total surface areas of each shape to get the total surface area of the figure:

324mm^2 + 243mm^2 + 729mm^2 = 1296mm^2

The surface area of the figure above is 1296mm^2

4 0

2 years ago