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2 years ago

10

An investment analyst has tracked a certain bluechip stock for the past six months and found that on any given day, it either go

es up a point or goes down a point. Furthermore, it went up on 25% of the days and down on 75%. What is the probability that at the close of trading four days from now, the price of the stock will be the same as it is today? Assume that the daily fluctuations are independent event

1 answer:

anastassius [24]2 years ago

7 0

Answer:

0.2109 or 21.09%

Step-by-step explanation:

In order to maintain the same price after two days, the stock must go up (U) on two days and go down (D) on two days, the sample space for this event is:

S={UUDD, UDUD, UDDU, DDUU, DUDU, DUUD}

There are 6 equally likely possible outcomes. The probability that the price of the stock will be the same as it is today is:

$P =6* (0.25*0.25*0.75*0.75)\\P=0.2109=21.09\%$

The probability is 0.2109 or 21.09%.

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What is the absolute value of -45/6. I need serious help

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Step-by-step explanation:

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1 year ago

9. A recent study examining the effects of sugar consumption on a middle

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Answer:

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Step-by-step explanation:

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Hope this Helps!!!

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2 years ago

The area of ABED is 49 square units. Given AGequals9 units and ACequals10 units, what fraction of the area of ACIG is represent

Mrac [35]

Answer:

The fraction of the area of ACIG represented by the shaped region is 7/18

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

In the square ABED find the length side of the square

we know that

AB=BE=ED=AD

The area of s square is

$A=b^{2}$

where b is the length side of the square

we have

$A=49\ units^2$

substitute

$49=b^{2}$

$b=7\ units$

therefore

$AB=BE=ED=AD=7\ units$

step 2

Find the area of ACIG

The area of rectangle ACIG is equal to

$A=(AC)(AG)$

substitute the given values

$A=(9)(10)=90\ units^2$

step 3

Find the area of shaded rectangle DEHG

The area of rectangle DEHG is equal to

$A=(DE)(DG)$

we have $DE=7\ units$

$DG=AG-AD=9-7=2\ units$

substitute $A=(7)(2)=14\ units^2$

step 4

Find the area of shaded rectangle BCFE

The area of rectangle BCFE is equal to

$A=(EF)(CF)$

we have

$EF=AC-AB=10-7=3\ units$

$CF=BE=7\ units$

substitute

$A=(3)(7)=21\ units^2$

step 5

sum the shaded areas

$14+21=35\ units^2$

step 6

Divide the area of of the shaded region by the area of ACIG

$\frac{35}{90}$

Simplify

Divide by 5 both numerator and denominator

$\frac{7}{18}$

therefore

The fraction of the area of ACIG represented by the shaped region is 7/18

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2 years ago