Answer:
The perimeter of the second square is 36 inches
Step-by-step explanation:
Given
Represent the sides of the squares with S1 and S2.
So:
--- Scale factor
--- perimeter of the first
Required
Calculate P2, the perimeter of the second
Represent the ratios of the perimeter:
Substitute 12 for P1
Equate both scale factors
Convert to fraction
Cross multiply
If the perimeter of the equilateral triangle is 18 cm then the width of the rectangle be 11.2 cm.
Given that the perimeter of the equilateral triangle be 18 cm and the perimeter of all the three triangles be 46.4 cm.
We are required to find the width of the rectangle.
Rectangle is basically the shape which is having opposite sides equal to each other.
Perimeter of equilateral triangle=3 *side
3* side=18
side=18/3
side=6
Since it is on the length of the rectangle so the length of rectangle be
6 cm.
Perimeter of all the three triangles=2*width of the rectangle+1 length+perimeter of 1 equilateral triangle.
T1 and T2 are the other triangles.
Suppose the width of the rectangle be x.
Perimeter=2*x+6+18
46.4=2x+24
2x=46.4-24
2x=22.4
x=11.2
So,the width of the rectangle is equal to 11.2 cm.
Hence if the perimeter of the equilateral triangle is 18 cm then the width of the rectangle be 11.2 cm.
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Answer:
Step-by-step explanation:
We need to match the slope of the function with the slope of the lines connecting the two points given. The slope of the lines are as follows:
Now,
the slope of the line BC matches with the slope of y=-3.5x-15.
the slope of the line DE matches with the slope of y=-0.5x-3.
the slope of the line HI matches with the slope of y=1.25x+4.
the slope of the line LM matches with the slope of y=5x+9.
and the slopes of the lines FG and JK do not match with any of the functions given.
Thus,