For this case we have an equation of the form:
h (t) = - (1/2) * a * t ^ 2 + vo * t + h0
Where,
vo: initial speed
a: acceleration:
h0: initial height.
We have the following equation:
h (t) = - 16t2 + 19t + 110
Therefore, the initial velocity is:
vo = 19 feet / s
Answer:
The initial velocity when the rock is thrown:
vo = 19 feet / s
If it's 125 + 0.375 then the answer is 125.375
and for the second it's 0.75
The answer is 4/7
Hope this helps
Thank you soo much
Solution (1) using angles of sectors:
Area of A = pi r^2 x 90/360 = 4.9
Area of B = pi r^2 x 270/360 = 14.2
Check: Area of A/B = 4.9/14.72 = 1/3 (as given)
Solution (2) using given info:
Area of B + Area of A = area of circle
Area of B + 1/3 Area of B = 3.14 * (2.5)^2 = 19.625
4/3 Area of B = 19.625
Area of B = 3/4 * 19.625
Area of B = 14.72
Area of A = 1/3 * 14.72 = 4.9
There is more solutions to this problem , like polar coordinate integration , and so on. for more just request.
Answer:
8
Step-by-step explanation:
24/3 = 8
