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DIA [1.3K]
3 years ago
10

Which of the following statements is TRUE based on the information given?

Mathematics
2 answers:
daser333 [38]3 years ago
5 0

Answer:

B

Step-by-step explanation:

The sum of the angle 1, 2 and 3 is 180 degrees , so B is the correct answer, because 70 + 110 = 180

Tom [10]3 years ago
4 0

Answer:

b

Step-by-step explanation:

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Katie earns 15$ each hour. Round to total time katie worked to the nearest hour and estimate her pay by using mulitplacation
Cloud [144]

Answer:

How long did she work for though?

Step-by-step explanation:

3 0
2 years ago
Find the integral using substitution or a formula.
Nadusha1986 [10]
\rm \int \dfrac{x^2+7}{x^2+2x+5}~dx

Derivative of the denominator:
\rm (x^2+2x+5)'=2x+2

Hmm our numerator is 2x+7. Ok this let's us know that a simple u-substitution is NOT going to work. But let's apply some clever Algebra to the numerator splitting it up into two separate fractions. Split the +7 into +2 and +5.

\rm \int \dfrac{x^2+2+5}{x^2+2x+5}~dx

and then split the fraction,

\rm \int \dfrac{x^2+2}{x^2+2x+5}~dx+\int\dfrac{5}{x^2+2x+5}~dx

Based on our previous test, we know that a simple substitution will work for the first integral: \rm \quad u=x^2+2x+5\qquad\to\qquad du=2x+2~dx

So the first integral changes,

\rm \int \dfrac{1}{u}~du+\int\dfrac{5}{x^2+2x+5}~dx

integrating to a log,

\rm ln|x^2+2x+5|+\int\dfrac{5}{x^2+2x+5}~dx

Other one is a little tricky. We'll need to complete the square on the denominator. After that it will look very similar to our arctangent integral so perhaps we can just match it up to the identity.

\rm x^2+2x+5=(x^2+2x+1)+4=(x+1)^2+2^2

So we have this going on,

\rm ln|x^2+2x+5|+\int\dfrac{5}{(x+1)^2+2^2}~dx

Let's factor the 5 out of the intergral,
and the 4 from the denominator,

\rm ln|x^2+2x+5|+\frac54\int\dfrac{1}{\frac{(x+1)^2}{2^2}+1}~dx

Bringing all that stuff together as a single square,

\rm ln|x^2+2x+5|+\frac54\int\dfrac{1}{\left(\dfrac{x+1}{2}\right)^2+1}~dx

Making the substitution: \rm \quad u=\dfrac{x+1}{2}\qquad\to\qquad 2du=dx

giving us,

\rm ln|x^2+2x+5|+\frac54\int\dfrac{1}{\left(u\right)^2+1}~2du

simplying a lil bit,

\rm ln|x^2+2x+5|+\frac52\int\dfrac{1}{u^2+1}~du

and hopefully from this point you recognize your arctangent integral,

\rm ln|x^2+2x+5|+\frac52arctan(u)

undo your substitution as a final step,
and include a constant of integration,

\rm ln|x^2+2x+5|+\frac52arctan\left(\frac{x+1}{2}\right)+c

Hope that helps!
Lemme know if any steps were too confusing.

8 0
3 years ago
Pls answer right away
Nostrana [21]

I will answer in just a second I’m showing work

6 0
3 years ago
If the xy-plane, the graph of y=x^2 and the circle with center (0,1) and radious 3 have how many points of intersection?
PSYCHO15rus [73]
<span>The answer to this question is c, two. The top arc of the circle intersects the y=x^2 as each 'limb' extends into infinity. The part of the circle below the x-axis does not intersect the circle. The y=x^2 curve does not dip below the x-axis, but does extend into infinity on both the negative x-axis and positive x-axis.</span>
4 0
3 years ago
What is the Surface area of a cylinder with a radius of 5in and height of 4in
9966 [12]

Answer:

282.74in 2

Step-by-step explanation:

r Radius = 5in

h Height = 4in

3 0
2 years ago
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