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WARRIOR [948]
3 years ago
11

Can someone help me please

Mathematics
2 answers:
anastassius [24]3 years ago
8 0
C=2*3.14*7.6
C=47.728
Round.
47.7

Therefore, the circumference is 47.7 m.
larisa86 [58]3 years ago
8 0

Answer:

47.728, so 50

Step-by-step explanation:

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Answer:

To solve your equation using the Equation Solver, type in your equation like x+4=5. The solver will then show you the steps to help you learn how to solve it on your own.

Step-by-step explanation:

5 0
3 years ago
If f(x)=x2+10sinx, show that there is a number c such that f(c)=1000.
gayaneshka [121]
F(x) is continuous for all x.

Pick a point and show that f(x) is either negative or positive. Pick another point and show that f(x) is negative, if positive, or positive, if negative.

At x = 30, f(30) - 1000 = 900 + 10sin(30) - 1000 ≤ 0
Now, show at another point f(x) - 1000 is positive, and hence, there would be root between 30 and such point.

Let's pick 40.
At x = 40, f(40) - 1000 = 1600 + 10sin(40) - 1000 ≥ 0

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7 0
3 years ago
1.
cluponka [151]

Answer:

Probably c

Step-by-step explanation:

Tbh

6 0
3 years ago
54394 plus 13768<br><br><br> Thank you
kakasveta [241]

Answer:

54394 + 13768 \\  \\  = 68162

5 0
3 years ago
Read 2 more answers
Find the difference quotient and simplify your answer. f(x) = 4x − x2, f(4 + h) − f(4) h , h ≠ 0
Anon25 [30]

The difference quotient and simplification will be    = [4 -h-2x]

The given equation is as follows:   f(x)= 4x - x²

For finding the quotient and further simplification we must follow the following steps:

[f(x + h) - f(x)] / h = [4(x + h) - (x + h)² - 4x + x²]/ h

<h3>What is simplification of algebraic operations?</h3>

Getting the functions in their lowest terms is known as simplification.

Brackets will get open and solved further;

[f(x + h) - f(x)] / h = [4(x + h) - (x + h)² - 4x + x²]/ h

[f(x + h) - f(x)] / h = [4h - h² - 2x]/ h  

Finally dividing the whole equation with h;

                                = [4 - h - 2x] 

Learn more about algebraic operations,

brainly.com/question/12485460

# SPJ1

7 0
1 year ago
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