Question

PLEASE HELP QUICK!! !!20 POINTS!!

Answer 1

The final table is in the attached picture.

Before beginning, you should note that:

To get rid of a fraction, this fraction should be multiplied that is equal to or is a multiple of its denominator.

This means that:

$\frac{1}{y} * ay = a$

Now, for the given:

We have the equation: $y = \frac{1}{3} x + 2$

The denominator of the fraction is 3, therefore to get rid of it we will need x to be a 3 or a multiple of 3.

Let's consider the x values to be -3, 0, 3 and 6.

For x = -3: $y = \frac{1}{3} (-3) + 2$ = -3 + 2 = -1 .....>First order pair is (-3,-1)

For x = 0: $y = \frac{1}{3} (0) + 2$ = 0 + 2 = 2 .....> Second order pair is (0,2)

For x = 3: $y = \frac{1}{3} (3) + 2$ = 1 + 2 = 3 .....> Third order pair is (3,3)

For x = 6: $y = \frac{1}{3} (6) + 2$ = 2 + 2 = 4 .....> Fourth order pair is (6,4)

Hope this helps :)