Answer: y= 2x +4
Step-by-step explanation:
1. To be able to write the equation of the line, you want to be able to find the slope first. To do so, rearrange the given equation x+2y=2 into slope-intercept form, which is y=mx+b
First subtract x from both side, which will give us 2y=2-x. Rearrange this to get 2y= -x+2. Then, divide both sides by 2. This will give us y= -1/2x+1
2. Now that you have the equation, look for the slope in the new equation; this will be the m value. In this case, the slope is -1/2. Since we are looking for a line that is perpendicular, we have to change the slope so that it is the opposite reciprocal. The opposite reciprocal of -1/2 is 2, so the slope of the equation we want to find is 2.
3. Next, all we have to do is plug the given ordered pair (-5, -6) and the slope that we found (m=2) into the point-slope equation, which is 
That will give us:
y+6 = 2(x+5)
4. Now, solve this equation.
y+6 = 2(x+5) --> distribute the 2 inside the parentheses
y+6 = 2x + 10 --> subtract 6 from both sides
y= 2x +4
Answer:
10 terms
Step-by-step explanation:
equate the sum formula to 55 and solve for n
n(n + 1) = 55 ( multiply both sides by 2 to clear the fraction )
n(n + 1) = 110 ← distribute parenthesis on left side
n² + n = 110 ( subtract 110 from both sides )
n² + n - 110 = 0 ← in standard form
Consider the factors of the constant term (- 110) which sum to give the coefficient of the n- term (+ 1)
the factors are + 11 and - 10 , since
11 × - 10 = - 110 and 11 - 10 = + 1 , then
(n + 11)(n - 10) = 0 ← in factored form
equate each factor to zero and solve for n
n + 11 = 0 ⇒ n = - 11
n - 10 = 0 ⇒ n = 10
However, n > 0 , then n = 10
number of terms which sum to 55 is 10
Answer:
Step-by-step explanation:
WHAT TOPIC IN MATH IS THIS?
Tossing a die will have 6 possible outcomes. Those are having sides that are number 1 to 6. The sample space of tossing 3 dice is equal to 6³ which is equal to 216. Now for the calculation of probabilities,
P(two 5s) = (1 x 1 x 5)/216
As we have to have the 5 in the die for two times, then for the 1 time, we can have all other numbers except 5. The answer is 5/216.
P(three 5s) = (1 x 1 x 1)/216 = 1/216
P(one 5 or two 5s) = (1 x 5 x 5)/216 + (1 x 1 x 5)/216 = 5/36
