A man is 50 years old. 8years ago, he was seven times as old as his daughter. How old is the daughter now?
2 answers:
Answer:
14 years old.
Step-by-step explanation:
The man was 42 years old 8 years ago.
When he was 42, he was 7 times as old as his daughter.
Let his daughter's age be x.
Her daughter was 6 years old 8 years ago.
8 years later she would be:
14 years old.
Answer:
14 years
Step-by-step explanation:
<u><em>Let the daughter's age before 8 years be y </em></u>
The man is 50 years old.
<em><u>8 years ago</u></em> , he was
=> 50-8 = 42 years
Also,
8 years ago,
7(y) = 42
=> Dividing both sides by 7
y = 6
Now after 8 years,
The daughter's age is,
=> 6 + 8 = 14 years
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The mean would be 8 since you would have to add all of them up which would give you 64 and then divide by the amount of numbers their are which is 8 so 64/8 = 8
