I'm assuming you're referring to problem 6. You are asked to find the number of x intercepts or roots, which is another term for "zero". I prefer the term root or x intercept as "zero" seems misleading. Anyways, all we do is count the number of times the graph crosses the x axis. This happens 4 times as shown in the attached image below. I have marked these points in red. The graph can directly cross over the x axis, or it can touch the x axis and then bounce back. Either way, it is considered an x intercept.
<h3>Answer: there are 4 x intercepts (or 4 roots)</h3>
Answer:
dilation..
Step-by-step explanation:
nop nopnop nop
<h2>Answer :-</h2>
As we know that,
Pythagoras triplet
1) a² + b² = c²
Let


<h3>Hence, A can't be Pythagoras triplet</h3>
2) a² + b² = c²


<h3>Therefore, B can be Pythagoras triplet</h3>
3)a² + b² = c²


<h3>Hence, C can't be Pythagoras triplet</h3>
4) a² + b² = c²


<h3>Hence, D can't be Pythagoras triplet</h3>
<h2 /><h2>Therefore :-</h2>
Only B can be Pythagoras triplet.
Answer:
S6tep-by-step explanation:
4^(11+8) = 4^19 is the solution
Answer:
D
Step-by-step explanation: