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3 years ago

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Can someone help me with my algebra 2 assignment.

1 answer:

gulaghasi [49]3 years ago

5 0

What’s the assignment

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Find the 11th term of the arithmetic sequence. <br> a3 = 20.5 and a8 = 13, a11 = ______. ...?

lianna [129]

In order to solve for a nth term in an arithmetic sequence, we use the formula written as:<span>

an = a1 + (n-1)d

where an is the nth term, a1 is the first value in the sequence, n is the term position and d is the common difference.

First, we need to calculate for d from the given values above.
<span>a3 = 20.5 and a8 = 13
</span>

an = a1 + (n-1)d
20.5 = a1 + (3-1)d

</span>an = a1 + (n-1)d
13 = a1 + (8-1)d
<span>
a1 = 23.5
d = -1.5

The 11th term is calculated as follows:

a11 = a1 + (n-1)d
a11= 23.5 + (11-1)(-1.5)
a11 = 8.5</span>

8 0

3 years ago

Does anyone know how to do this?

SCORPION-xisa [38]

Answer:

i think he is correct

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Arnie's car used 100 cups of gasoline during a drive. He paid $3.12per gallon for gas how much did the gas cost

Alla [95]

Okay so in a gallon there are 16 cups, in this case 100 cups is equivalent to 6.25 gallons. 6.25 times 3.12= 19.5

Therefore $19.5 is how much the gas cost!

4 0

3 years ago

Read 2 more answers

Jose can read 7 pages of his book in 5 minutes. At this rate, how long will it take him to read the entire 175 page book?

il63 [147K]

125 minutes, or 2 hours and 5 minutes.

$\frac{5}7 = \frac{x}{175}$
cross multiply
5*175=7x
875=7x
$\frac{875}7=x$
125=x

5 0

3 years ago

Read 2 more answers

Trapezoids and kites

lisov135 [29]

QUESTION 3

The sum of the interior angles of a kite is $360\degree$ .

$\Rightarrow 36\degree +70\degree+m$ .

$\Rightarrow 106\degree+m$ .

$\Rightarrow m$ .

$\Rightarrow m$ .

But the two remaining opposite angles of the kite are congruent.

$\Rightarrow m$

$\Rightarrow m$ .

$\Rightarrow 2m$ .

$\Rightarrow m$ .

$\Rightarrow m$ .

QUESTION 4

RH is the hypotenuse of the right triangle formed by the triangle with side lengths, RH,12, and 20.

Using the Pythagoras Theorem, we obtain;

$|RH|^2=12^2+20^2$

$|RH|^2=144+400$

$|RH|^2=544$

$|RH|=\sqrt{544}$

$|RH|=4\sqrt{34}$

QUESTION 5

The given figure is an isosceles trapezium.

The base angles of an isosceles trapezium are equal.

Therefore $m$

QUESTION 6

The measure of angle Y and Z are supplementary angles.

The two angles form a pair of co-interior angles of the trapezium.

This implies that;

$m$

$\Rightarrow m$

$\Rightarrow m$

QUESTION 7

The sum of the interior angles of a kite is $360\degree$ .

$\Rightarrow 48\degree +110\degree+m$ .

$\Rightarrow 158\degree+m$ .

$\Rightarrow m$ .

$\Rightarrow m$ .

But the two remaining opposite angles are congruent.

$\Rightarrow m$

$\Rightarrow m$ .

$\Rightarrow 2m$ .

$\Rightarrow m$ .

$\Rightarrow m$ .

QUESTION 8

The diagonals of the kite meet at right angles.

The length of BC can also be found using Pythagoras Theorem;

$|BC|^2=4^2+7^2$

$\Rightarrow |BC|^2=16+49$

$\Rightarrow |BC|^2=65$

$\Rightarrow |BC|=\sqrt{65}$

QUESTION 9.

The sum of the interior angles of a trapezium is $360\degree$ .

$\Rightarrow m$ .

$\Rightarrow m$ .

But the measure of angle M and K are congruent.

$\Rightarrow m$ .

$\Rightarrow m$ .

$\Rightarrow m$ .

$\Rightarrow m$ .

6 0

3 years ago