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Masja [62]
3 years ago
11

Write and solve an equation for the total number of possible combinations from flipping a coin 10 times. Please help quick, I'm

trying to work ahead in my courses so i finish my trimester early, and I've already done two of my courses early
Mathematics
2 answers:
Soloha48 [4]3 years ago
5 0

Answer:

1024

Step-by-step explanation:

Given that a coin is flipped 10 times.

We know flipping a coin results in two outcomes Head or Tail

When two coins are flippes we get total outcomes as 4 = 2 square

When three coins are flippes we get total outcomes as 8 = 2 cue

Hence in general, if a coin is flipped n times total possible outcomes would be

2^n

Here n =10 (given)

Hence total possible outcomes

=2^{10} =1024

Furkat [3]3 years ago
3 0
The total number of possible combinations from flipping a coin 10 times is 2^10 = 1024.
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65.56°

Step-by-step explanation:

We know that if we take dot product of two vectors then it is equal to the product of magnitudes of the vectors and cosine of the angle between them

That is let p and q be any two vectors and A be the angle between them

So, p·q=|p|*|q|*cosA

⇒cosA=\frac{u.v}{|u||v|}

Given u=-8i-3j and v=-8i+8j

|u|=\sqrt{(-8)^{2}+ (-3)^{2}} =8.544

|v|=\sqrt{(-8)^{2}+ (8)^{2}} =11.3137

let A be angle before u and v

therefore, cosA=\frac{u.v}{|u||v|}=\frac{(-8)*(-8)+(-3)*(8)}{8.544*11.3137} =\frac{40}{96.664}

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Therefore angle between u and v is 65.56°

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Method 2: By Prime FactorsList all prime factors of each denominator, and find the union of these primes.
Therefore, the LCD is <span>2 x 2 = 4
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</span>\frac{1 x 2}{2 x 2} -  \frac{3}{4}
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