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tekilochka [14]
3 years ago
8

Avery's yard has an area of 5/4 acres, and Logan's yard has an area of 3/2 acres. What is the ratio of the area of Avery's yard

to the area of Logan's yard? plz explain and show work.
A. \frac{4}{5} to 1
B. \frac{5}{6} to 1
C. \frac{2}{3} to 1
D. \frac{8}{5} to 1
Mathematics
2 answers:
Sever21 [200]3 years ago
8 0

Answer:

The correct answer is option B

Step-by-step explanation:

Avery's yard area = \frac{5}{4} \\ acres

Logan's yard area = \frac{3}{2} \\ acres

Ratio of the area of Avery's yard to the area of Logan's yard

\frac{5/4}{3/2} \\= \frac{(5 * 2)}{(4 * 3)} \\= \frac{10}{12}\\= \frac{5}{6}\\

SOVA2 [1]3 years ago
3 0

Answer:

5/6 to 1

Step-by-step explanation:

Hello

You have to divide (5/4)/(3/2) and to apply the ear´s law.

The result is = 5/6

Best regars

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Reverse the two digits of my age, divide by three, add 20, and the result is my age. How many years old am I
lapo4ka [179]

Answer:

  • 48 years old.

Step-by-step explanation:

Let the age be xy or 10x + y.

Reverse the two digits of my age, divide by three, add 20, and the result is my age, convert this to equation:

  • (10y + x)/3 + 20 = 10x + y
  • (10y + x)/3 = 10x + y - 20
  • 10y + x = 3(10x + y - 20)
  • 10y + x = 30x + 3y - 60
  • 30x - x + 3y - 10y = 60
  • 29x - 7y = 60

We should consider both x and y are between 1 and 9 since both the age and its reverse are 2-digit numbers.

Possible options for x are:

  • 29x ≥ 7*1 + 60 = 67 ⇒ x > 2, at minimum value of y,

and

  • 29x ≤ 7*9 + 60 = 123 ⇒ x < 5, at maximum value of y.

So x can be 3 or 4.

<h3>If x = 3</h3>

  • 29*3 - 7y = 60
  • 87 - 7y = 60
  • 7y = 27
  • y = 27/7, discarded as fraction.

<h3>If x = 4</h3>

  • 29*4 - 7y = 60
  • 116 - 7y = 60
  • 7y = 56
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So the age is 48.

6 0
2 years ago
An island has some portion submerged in water. Point X on the island is at negative 9 over 2 feet from the surface of the sea. P
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It means, Point X is in more depth as compared to Point Y.

Hope this helps!
8 0
4 years ago
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A tent has the dimensions shown in the diagram. Find the area of the groundsheet needed to fit inside the tent. Round your answe
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Apologies if the diagram is a bit confusing

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4 years ago
The following prices, in dollars, of 7.5-cubic-foot refrigerators were recorded from a random sample. 314 305 344 283 285 310​ 3
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Answer:

t=\frac{310.9-300}{\frac{31.09}{\sqrt{10}}}=1.109      

The degrees of freedom are given by:

df=n-1=10-1=9  

And the p value would be given by:

p_v =P(t_{9}>1.109)=0.148  

Since the p value is higher than the significance level of 0.05 we don't have enough evidence to conclude that the true mean is significantly higher than $300 because we FAIL to reject the null hypothesis.

Step-by-step explanation:

Information given

314 305 344 283 285 310​ 383​ 285​ 300​ 300

We can calculate the sample mean and deviation with the following formula:

\bar X =\frac{\sum_{i=1}^n X_i}{n}

s =\sqrt{\frac{\sum_{i=1}^n (x_i -\bar X)^2}{n-1}}

\bar X=310.9 represent the sample mean      

s=31.09 represent the standard deviation for the sample      

n=10 sample size      

\mu_o =300 represent the value to test

\alpha=0.05 represent the significance level

t would represent the statistic

p_v represent the p value

Hypothesis to test

We want to verify if the true mean is greater than 300, the system of hypothesis would be:      

Null hypothesis:\mu \leq 300      

Alternative hypothesis:\mu > 300      

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)      

Replacing the info given we got:

t=\frac{310.9-300}{\frac{31.09}{\sqrt{10}}}=1.109      

The degrees of freedom are given by:

df=n-1=10-1=9  

And the p value would be given by:

p_v =P(t_{9}>1.109)=0.148  

Since the p value is higher than the significance level of 0.05 we don't have enough evidence to conclude that the true mean is significantly higher than $300 because we FAIL to reject the null hypothesis.

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