If you have 50. and want to make it 5000 you can move the decimals point over 2 which would also be ×100
A.)
<span>s= 30m
u = ? ( initial velocity of the object )
a = 9.81 m/s^2 ( accn of free fall )
t = 1.5 s
s = ut + 1/2 at^2
\[u = \frac{ S - 1/2 a t^2 }{ t }\]
\[u = \frac{ 30 - ( 0.5 \times 9.81 \times 1.5^2) }{ 1.5 } \]
\[u = 12.6 m/s\]
</span>
b.)
<span>s = ut + 1/2 a t^2
u = 0 ,
s = 1/2 a t^2
\[s = \frac{ 1 }{ 2 } \times a \times t ^{2}\]
\[s = \frac{ 1 }{ 2 } \times 9.81 \times \left( \frac{ 12.6 }{ 9.81 } \right)^{2}\]
\[s = 8.0917...\]
\[therfore total distance = 8.0917 + 30 = 38.0917.. = 38.1 m \] </span>
It would be 6(4a2 - 3)
you would factor out just the 6 because the 18 doesn’t a a term with it like 34a2 does. then just divide normally to get ur answer 6(4a2 - 3)
Answer:
I know the answer
Step-by-step explanation:
x = random number then y = x + y then x = 68 So we can conclude
Answer:
Step-by-step explanation:
Given 
(A) 
We know that Sin(A + B) = SinA cosB + cosAsinB
Substituting in the above formula we get:
(B) Cos(A + B) = CosAcosB - SinASinB
(C) Tan(A + B) = 
From the above obtained values this can be calculated and the value is .
