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Mariulka [41]
3 years ago
14

Based on the slipes of the equation, how many solutions does this system have Y=3x-4 y=-2x+7

Mathematics
1 answer:
Dmitrij [34]3 years ago
8 0

Answer:

The slopes are m=3 and m=-2

There is only one solution

Step-by-step explanation:

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What is the value of the expression 2^2 + 4^2 ÷ 2^2?
Dennis_Churaev [7]

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The answer is C.

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8 0
3 years ago
Solve for x: 4 − (x + 2) < −3(x + 4)
jeyben [28]
4 - (x+2) < -3(x+4)

4 -1(x) -1(2) < -3(x) -3(4)
4 - x - 2 < -3x -12
 <u>  +3x        +3x      </u>
<u />2 + 2x    <   -12
<u>-2                   -2    
</u>      2x     < -14
<u /> <u>     ÷2          ÷2    </u>
        x      < -7

assume that x = -8

4 - (-8 + 2) < -3(-8 + 4)
4 - (-6) < -3(-4)
4 + 6 < 12
10 < 12  the inequality is true.
8 0
3 years ago
Solve for x. 78(−32−48x)+36=23(−33x−18)−10x Enter your answer in the box. x =
Nina [5.8K]

Answer:

x=-0.688

Step-by-step explanation:

-2496-3744x+36 = -759x-414-10x

-2460-3744x = -769x-414

-2975x = 2046

5 0
3 years ago
Miguel has one dollar in change. He has twice as many nickels as dimes. He has 14 more pennies than quarters. What coins does he
marin [14]
D=dimes
n=niclkes
p=pennies
q=quarters

1 dollar (100 cents)
2 times as many nickles as dimes
n=2d

14 more pennies than quarters
p+14=q

and total is 1 dollar so
25q+10d+5n+p=100
ok so we must use logic
the max number of quarters in a dolar is 4
but there are pennies so max is 3
so q=1,2, or 3
therefor p=15,16 or, 17

also, the rest of te coins are only multipules of 5 so the sum amount of pennies and quartes must add to a multiplule of 5

if q=1 and p=15, total is 40 cents
if q=2 and p=16, total is 66 cents
if q=3 and p=17, total is 92 cents
only 40 cents is a multiplule of 10

1 quarter and 15 pennies
now we are having
40 cents is pennies and quartesrs
therfor 100-40=60 cents is nickles and dimes
60=5n+10d
n=2d
sub
60=5(2d)+10d
60=10d+10d
60=20d
divide both sides by 20
3=d
sub
n=2d
n=2(3)
n=6

6 nickles
3 dimes




answer is
1 quarter
3 dimes
6 nickles
15 pennies
4 0
3 years ago
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