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3 years ago

Find the domain of y= √3x+3

Mathematics

1 answer:

liubo4ka [24]3 years ago

6 0

Answer:

it's hard to tell the exact question being asked...

y = $\sqrt{3x} + 3$

y = $\sqrt{3x+3}$

if y = $\sqrt{3x} + 3$ then Domain is [0 ,∞ )

if y = $\sqrt{3x+3}$ then Domain is [-1 ,∞ )

Step-by-step explanation:

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NARA [144]

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3 years ago

Solve: In 2x + In 2 = 0 DONE

pychu [463]

Answer:

$x=\frac{1}{4}$

Step-by-step explanation:

We can use some logarithmic rules to solve this easily.

Note: Ln means $Log_e$

Now, lets start with the equation:

$ln(2x) + ln(2) = 0\\ln(2x) = -ln(2)$

Writing left side with logarithmic base e, we have:

$Log_{e}(2x) = -ln(2)$

We can now use the property shown below to make this into exponential form:

$Log_{a}b=x\\means\\a^x=b$

So, we write:

$Log_{e}(2x) = -ln(2)\\e^{-ln(2)}=2x$

We recognize another property of exponentials:

$a^{bc}=(a^{b})^{c}$

So, we write:

$e^{-ln(2)}=2x\\(e^{ln(2)})^{-1}=2x$

Also, another property of natural logarithms is:

$e^{(ln(a))}=a$

Now, we simplify:

$(e^{ln(2)})^{-1}=2x\\(2)^{-1}=2x\\\frac{1}{2}=2x\\x=\frac{\frac{1}{2}}{2}\\x=\frac{1}{4}$

This is the answer.

7 0

3 years ago

Someone please help me

gizmo_the_mogwai [7]

(3/20)^3

27/8000

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3 years ago

What is the value of 7P3

emmainna [20.7K]

7P3= 7!/(7-3)!
= 7!/4!
= 7*6*5
= 210

C.210

5 0

3 years ago

Simply x+1/x^2+6x+5 step by step Pls

scoray [572]

Answer:

1 / (x+5)

Step-by-step explanation:

Factor the denominator

(x+1)/ (x+5)(x+1)

Cancel both (x+1)

=1/(x+5)

7 0

3 years ago