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frez [133]
3 years ago
14

The graph below shows two polynomial functions, f(x) and g(x):

Mathematics
2 answers:
Marianna [84]3 years ago
7 0
<span>A. g(x) is an even degree polynomial with a positive leading coefficient.
because g(x) curves upward at both ends</span>
svetoff [14.1K]3 years ago
6 0
Hello there.

<span>Which of the following statements is true about the graph above?

</span><span>A. g(x) is an even degree polynomial with a positive leading coefficient.</span>
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What is the y-intercept for the equation y= 11x + 1?<br> -11<br> -1<br> 1<br> 11
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Step-by-step explanation:

The y-intercept in the equation is 1 because the equation uses the format y=mx+b. The b in y=mx+b represents the y-intercept So, in this equation the y-intercept is 1 because b=1.

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A bag holds 6 green, 9 red and 4 blue marbles a marble is selected at random what is the probability of not selecting a red marb
Butoxors [25]

Answer:

The probability of not selecting a red marble, P(R)'  = 10/19

Step-by-step explanation:

The probability of an event occurring is equal to the number of ways the required event occurs divided by the number of possible outcomes

The number of ways of an event not occurring is 1 less the probability of the event occurring

The number of green marbles in the bag = 6

The number of red marbles in the bag = 9

The number of blue marbles in the bag = 4

The sum of the marbles in the bag, n = 6 + 9 + 4 = 19

The number of ways of selecting a red marble = 9 ways

The probability of selecting a red marble = 9 ways/19 marbles = 9/19

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The probability of not selecting a red marble P(R)' = 10/19

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3 years ago
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Which of the following is the complete list of roots for the polynomial function f (x) = (x squared 6 x 8) (x squared 6 x 13)? –
Sunny_sXe [5.5K]

The roots of the given polynomial function is {-4, -2, -3 + 2i, -3 - 2i}.

<h3>How to get the roots of the polynomial?</h3>

Here we have the polynomial function:

f(x) = (x^2 + 6x + 8)*(x^2 + 6x + 13)

So we just need to find the roots of the two quadratic functions, to do that, we use Bhaskara's formula.

For the first one, we have:

x = \frac{-6 \pm \sqrt{6^2 - 4*8} }{2} \\\\x = \frac{-6 \pm 2}{2}

So the two solutions are:

x = (-6 - 2)/2 = -4

x = (-6 + 2)/2 = -2

For the second quadratic we have:

x = \frac{-6 \pm \sqrt{6^2 - 4*13} }{2} \\\\x = \frac{-6 \pm 4i}{2}

So the two solutions are:

x = -3 + 2i

x = -3 - 2i

Finally, the list is:

{-4, -2, -3 + 2i, -3 - 2i}

If you want to learn more about polynomials:

brainly.com/question/4142886

#SPJ4

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