Answer:
s = 6 m
Step-by-step explanation:
The value of the velocity v is given as:
m/s
To find s, we have to integrate and apply the initial values of s = o when t = 0:
When t = π/2, s will be:
s = -3cos(2 * π/2) + 3
s = -3cos(π) + 3
s = -3(-1) + 3
s = 3 + 3
s = 6 m
Well I don't get what the other parts of the question is asking, but they can make 240 packs of pencils.
Step-by-step explanation:
Initial velocity(u) = 60 km/hr = 50/3 m/s
final velocity(v)= 0 (stops at rest)
acceleration(a) = -0.05 m/s²
display (s)=?
v²-u²=2as
0²- (50/3)= 2(-0.05)s
2500/9= 0.1s
s= 25000/9 m
The question states that both parts of Noshi's desk were shaped like trapezoids and both had a height of 3.
We know that the formula for area of a trapezoid is (a+b)/2 * h, where a and b are bases of the trapezoid and h is the height. Note: This is like any other form of trying to find the area, because we are doing base times height, however, we need to divide the sum of the bases by 2 to find the average base length.
Let's call the first trapezoid on the left Trapezoid A and the second slanted trapezoid Trapezoid B.
Area of Trapezoid A = (a+b)/2 * h = (5+8)/2 * 3 = 13/2 * 3 = 6.5 * 3 = 19.5 feet
Area of Trapezoid B = (a+b)/2 * h = (4+9)/2 * 3 = 13/2 * 3 = 6.5 * 3 = 19.5 feet
To find the area of Noshi's total desk, we simply need to add the areas of Trapezoid A and Trapezoid B together.
19.5 feet + 19.5 feet = 39 feet
Therefore, the area of Noshi's desk is 39 feet.
Hope this helps! :)
For this case we have a function of the form 
, where 
We must find the value of the function when 
, that is, we must find f (3). So:
So
Answer:
