Hello : f'(7) = the slope of the tangent line : let A(7,4) B(0,3)<span> <span>the slope is : (YB - YA)/(XB -XA)= (3-4)/(0-7) = -1/-7 = 1/7=f'(7) the equation of the tangent line is : y-3 = 1/7 (x-0) y = (1/7)x+3 the line tangent and the graph of : f </span></span><span>passes through the point A(7, 4) x= 7 y=4 so : f(7) =4</span>