How long will it take a rocket traveling at 8 km/s to reach 20 km?

How many 3/5 are in 1/3

Alenkinab [10]

Answer:

4/15

Step-by-step explanation:

6 0

3 years ago

Marlene's taxable income is $95,000. Use this tax schedule to calculate the total amount she owes in taxes. A. 12,88.75 B. 17,90

zheka24 [161]

The answer is C.

Since here taxable income is over $77,100 and below $160,850, her tax is $15,698.75 + [.28*($95,000 - $77,100)].

Tax = $15,698.75 + [.28*($17,900)].
= $15,698.75 + [$5012].
= $20,710.75

Thank you for posting this question. Please feel free to ask me more.

7 0

3 years ago

Determine the solution to the system of equation below, algebraically. 5x+3y=28 x+y=8

VladimirAG [237]

Is this what you're asking for?

5 0

3 years ago

Help me please and thank you!

mamaluj [8]

7^6 is the correct answer

8 0

3 years ago

A population has a mean of 200 and a standard deviation of 50. Suppose a sample of size 100 is selected and x is used to estimat

zmey [24]

Answer:

a) 0.6426 = 64.26% probability that the sample mean will be within +/- 5 of the population mean.

b) 0.9544 = 95.44% probability that the sample mean will be within +/- 10 of the population mean.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .