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V125BC [204]
3 years ago
7

Tommie paid $17.50 to buy 6 youth tickets and 1 adult ticket to a school carnival. Susan paid $22.50 to buy 3 youth tickets and

3 adult tickets at the carnival. What was the price of an adult ticket?
Mathematics
1 answer:
bekas [8.4K]3 years ago
3 0
6y + a = 17.50
3y + 3a = 22.50...multiply by -2
--------------------
6y + a = 17.50
-6y - 6a = - 45...result of multiplying by -2
-------------------add
-5a = - 27.50
a = -27.50 / -5
a = 5.50 <== price of adult ticket (a)
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Answer:

4. A

5. B

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4. I'll solve question four first:

The two marked points on the line are (-2, -3)&(2, 5). Using the formula to find slope(y2-y1/x2-x1), substitute in the points.

5--3/2--2 or 8/4;simplified to 2/1 or 2.

Now use point-slope form: y-y1 = m(x-x1)

y--3 = 2(x--2): Substitute in the values of y1, m, and x1.

y+3 = 2x + 4: Distribute.

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5. Do the same for question 5.

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3 years ago
What are factore of 625
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Annie estimates that the height of a bookcase is 78.25 in. The actual height is 75.50 in. To the nearest tenth of a percent, wha
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Answer:

\displaystyle x \approx 8.2

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Trigonometry</u>

[Right Triangles Only] SOHCAHTOA

[Right Triangles Only] sinθ = opposite over hypotenuse

Step-by-step explanation:

<u>Step 1: Identify Variables</u>

Angle θ = 23°

Opposite Leg = <em>x</em>

Hypotenuse = 21

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Substitute in variables [sine]:                                                                         \displaystyle sin(23^\circ) = \frac{x}{21}
  2. [Multiplication Property of Equality] Isolate <em>x</em>:                                              \displaystyle 21sin(23^\circ) = x
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Sergeeva-Olga [200]
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1.25       =    1.25

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6 0
3 years ago
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