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Dafna11 [192]
1 year ago
12

pictured below are stacks of solid cubes. determine the number of cubes in the stack and the number of faces glued together.

Mathematics
1 answer:
Iteru [2.4K]1 year ago
5 0

Solution

For this case we need to find the number of cubes in the stack given so then we can do this:

The first line present 5 cubes

The second line present 5 cubes

And the last line we got:

10 cubes

Then the total of cubes are:

10 +5+5 = 20 cubes

If we need to find the number of faces we can do the following:

5+ 4+ 4+4 +4 +1 + (5+4+4+4+4+1 ) + (5+4+4+4+4+1 ) + (5+ 4+4+4 +4 )

And solving we got:

22+22+ 22+21= 87

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Describe the end behavior of a 14th degree polynomial with a positive leading coefficient.
DiKsa [7]

<u><em>Answer:</em></u>

1)

f(x)→ ∞ when x→∞ or x→ -∞.

2)

when  x→ ∞ then f(x)→ -∞

        and when x→ -∞ then f(x)→ ∞

<u><em>Step-by-step explanation:</em></u>

<em>" The </em><em>end behavior</em><em> of a polynomial function is the behavior of the graph of as approaches positive infinity or negative infinity. The degree and the leading coefficient of a polynomial function determine the end behavior of the graph "</em>

1)

a 14th degree polynomial with a positive leading coefficient.

Let f(x) be the polynomial function.

Since the degree is an even number and also the leading coefficient is positive so when we put negative or positive infinity to the function i.e. we put x→∞ or x→ -∞ ; it will always lead the function to positive infinity

i.e. f(x)→ ∞ when x→∞ or x→ -∞.

2)

a 9th degree polynomial with a negative leading coefficient.

As the degree of the polynomial is odd and also the leading coefficient is negative.

Hence when x→ ∞ then f(x)→ -∞ since the odd power of x will take it to positive infinity but the negative sign of the leading coefficient will take it to negative infinity.

When x→ -∞ then f(x)→ ∞; since the odd power of x will take it to negative infinity but the negative sign of the leading coefficient will take it to positive infinity.

Hence, when  x→ ∞ then f(x)→ -∞

        and when x→ -∞ then f(x)→ ∞



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x = 1

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\frac{4x-1}{2}+\frac{3x+4}{3}= \frac{23}{6}

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