All categories

1 year ago

I do not understand

Mathematics

1 answer:

Vanyuwa [196]1 year ago

8 0

$\huge \sf༆ Answer ༄$

Here's the solution ~

$\sf \dfrac{5 {}^{6} }{5 {}^{1} }$

$\sf 5 {}^{6 - 1}$

$\sf {5}^{5}$

You might be interested in

MrRissso [65]

Answer:

Step-by-step explanation:

3 0

2 years ago

Miguel tells his teacher1/5 is the same as 20%. Which best justifies Miguel’s answer? a.5 goes into 100 twenty times, so 20% is

svetoff [14.1K]

Answer:

C. 5 goes into 100 twenty times, and 1 times 20 is 20

Step-by-step explanation:

Since, we know that when we multiply both numerator and denominator of a fraction by a same number then we obtain an equivalent fraction,

Here, the given fraction,

$\frac{1}{5}$

By the above statement,

$\frac{1}{5}=\frac{1\times 20}{5\times 20}=\frac{20}{100}$

Now,

$a\%=\frac{a}{100}$

$\implies \frac{20}{100}=20\%$

Hence,

$\frac{1}{5}=20\%$

Option C is correct.

3 0

2 years ago

Read 2 more answers

Pl help it’s for a grade

allsm [11]

Answer:

(^6√x^5) (√y)

(The 6 belongs in the left on top of the square root btw)

For x the 6 moves to the front of the square root while the 5 becomes the power of x.

For y, the power to the 1/2 is the same as a square root.

5 0

2 years ago

Can someone plz help me with this!

asambeis [7]

Answer:

(arranged from top to bottom)

System #3, where x=6

System #1, where x=4

System #7, where x=3

System #5, where x=2

System #2, where x=1

Step-by-step explanation:

System #1: x=4

$2x+y=10\\x-3y=-2$

To solve, start by isolating your first equation for y.

$2x+y=10\\y=-2x+10$

Now, plug this value of y into your second equation.

$x-3(-2x+10)=-2\\x+6x-30=-2\\7x=28\\x=4$

System #2: x=1

$x+2y=5\\2x+y=4$

Isolate your second equation for y.

$2x+y=4\\y=-2x+4$

Plug this value of y into your first equation.

$x+2(-2x+4)=5\\x+(-4x)+8=5\\x-4x+8=5\\-3x=-3\\x=1$

System #3: x=6

$5x+y=33\\x=18-4y$

Isolate your first equation for y.

$5x+y=33\\y=-5x+33$

Plug this value of y into your second equation.

$x=18-4(-5x+33)\\x=18+20x-132\\-19x=-114\\x=6$

System #4: all real numbers (not included in your diagram)

$y=13-2x\\8x+4y=52$

Plug your value of y into your second equation.

$8x+4(13-2x)=52\\8x+52-8x=52\\0=0$

<em>all real numbers are solutions</em>

System #5: x=2

$x+3y=5\\6x-y=11$

Isolate your second equation for y.

$6x-y=11\\-y=-6x+11\\y=6x-11$

Plug in your value of y to your first equation.

$x+3(6x-11)=5\\x+18x-33=5\\19x=38\\x=2$

System #6: no solution (not included in your diagram)

$2x+y=10\\-6x-3y=-2$

Isolate your first equation for y.

$2x+y=10\\y=-2x+10$

Plug your value of y into your second equation.

$-6x-3(-2x+10)=-2\\-6x+6x-30=-2\\-30=-2$

<em>no solution</em>

System #7: x=3

$y=10+x\\2x+3y=45$

Plug your value of y into your second equation.

$2x+3(10+x)=45\\2x+30+3x=45\\5x=15\\x=3$

3 0

2 years ago

Given A is between Y and Z YA = 5.5, AZ = 2x, and YZ = 41.5 =, find AZ

morpeh [17]

YZ = YA + AZ
41.5 = 5.5 + AZ
AZ = 41.5 - 5.5
AZ = 36

So, your final answer is AZ = 36

Hope this helps!

4 0

2 years ago

Read 2 more answers