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2 years ago

I do not understand

Mathematics

1 answer:

Vanyuwa [196]2 years ago

8 0

$\huge \sf༆ Answer ༄$

Here's the solution ~

$\sf \dfrac{5 {}^{6} }{5 {}^{1} }$

$\sf 5 {}^{6 - 1}$

$\sf {5}^{5}$

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Find the volume of a right circular cone that has a height of 3.9 ft and a base with a circumference of 16.3 ft. Round your answ

MissTica

Answer:

The answer to your question is Volume = 27.5 ft³

Step-by-step explanation:

Data

Volume = ?

height = 3.9 ft

Circumference = 16.3 ft

Process

1.- Calculate the radius of the Cone

Circumference = 2πr = 16.3 ft

-Solve for r

r = 16.3/2π

r = 16.3/6.28

r = 2.5955 ft

2.- Calculate the volume

Volume = 1/3πr²h

-Substitution

Volume = 1/3(3.14)(2.5955)²(3.9)

-Simplification

Volume = 1/3(82.4966)

-Result

Volume = 27.5 ft³

8 0

3 years ago

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Solve the equation.<br><br> 3(k−6)=15

Natali [406]

Answer:

K = 11

Step-by-step explanation:

3(k - 6) = 15

3k - 18 = 15

3k = 15 + 18

3k = 33

K = 33/3

K = 11

Thus, the value of K is 11

8 0

2 years ago

Find the value of x

kodGreya [7K]

Answer:

Last Option

Step-by-step explanation:

We have a triangle and we know its three sides.

We want to find one of your anguos. Then we use the cosine theorem.

$c ^ 2 = a ^ 2 + b ^ 2 -2abcosx$

Where

$c = 14\\a = 11\\b = 19$

Now we solve for x from the equation

$c ^ 2 = a ^ 2 + b ^ 2 -2abcosx\\\\\\14^2 = 11^2 + 19^2 -2(11)(19)cosx\\\\14^2 -11^2 -19^2 = 2(11)(19)cosx\\\\-286=2(11)(19)cosx\\\\cosx = \frac{-286}{2(11)(19)}\\\\x = arcos(\frac{-286}{2(11)(19)})\\\\x = 46.8\°$

6 0

3 years ago

Read 2 more answers

Write the formula for an exponential function with initial value 300 and decay factor 0.73

postnew [5]

Answer: 300*0.73^x

Step-by-step explanation:

300 is the initial value and every time x goes up by 1, the value get multiplied by 0.73

when x=3

then the value would be 300*0.73*0.73*0.73 or 300*0.73^3

then for x amount of times the equation would be 300*(0.73 x times ) or 300*0.73^x

8 0

2 years ago

The volume of construction work was increased by 60% but the productivity of labor increased by only 25%. By what percent must t

Sergeu [11.5K]

Answer: 28 %

Step-by-step explanation:

Let, Initially,

V be the volume of construction work

r be the productivity of labor

n be the number of days

x be the number workers.

Thus, V = r × n × x ------------(1)

Now, According to the question,

The volume of construction work was increased by 60% but the productivity of labor increased by only 25%.

Therefore,

Final volume of the work = 160% of V = 1.6 V

Final productivity = 125% of r = 1.25 r

Also, the time is same in both conditions,

Final time taken = n

Let y be the number of people after changes.

Thus, 1.6 V = 1.25 r × n × y -----(2)

Dividing equation (1) by equation (2)

We get, y = 1.60 x/1.25

Thus, the changes in the number of workers

= $\frac{(\frac{1.60x}{1.25}-x) }{x}\times 100$

= 0.28 × 100

= 28 %

5 0

3 years ago