Help me plz......................

Mathematics

1 answer:

alex41 [277]3 years ago

4 0

The picture has the answer and here are the calculations:

62 X 9 = 558

62 X 4 = 248

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Which of the following equations could be the result of using the comparison method to solve the system shown?

masya89 [10]

Answer:

6-2y=4y+8

since you show x through y

Answer:

The result that is obtained on comparing the system of equations in order to get the solution to the system of equations is:

6 -2y =4y + 8

Step-by-step explanation:

We are given a system of equations in term of variable x and y as follows:

x + 2y = 6 --------(1)

x - 4y = 8-------------(2)

From equation (1) we have the value of x in terms of y as:

x=6-2y

From equation (2) we have the value of x in terms of y as:

x=8+2y

Hence, on equation the above two values of 'x' we obtain:

6 - 2y = 4y + 8

ghope this helps

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2 years ago

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Romashka [77]

Answer:Wednesday I think

Step-by-step explanation:

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3 years ago

WILL NAME BRAINLIST PLEASE

algol13

Answer:

x = -4y

<em>Hope that helps! :)</em>

<em>-Aphrodite</em>

Step-by-step explanation:

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3 years ago

Square root of 32 x square root of 1 over 18

lisov135 [29]

<h3>Solution:</h3>

$\sqrt{32} \times \sqrt{ \frac{1}{18} } \\ = \sqrt{32} \times \frac{ \sqrt{1} }{ \sqrt{18} } \\ = \sqrt{32} \times \frac{1}{ \sqrt{18} } \\ = \frac{\sqrt{2 \times 2 \times 2 \times 2 \times 2}}{ \sqrt{2 \times 3 \times 3} } \\ = \frac{ \sqrt{ {2}^{2} \times {2}^{2} \times 2} }{ \sqrt{2 \times {3}^{2} } } \\ = \frac{2 \times 2 \times \sqrt{2} }{3 \times \sqrt{2} } \\ = \frac{4 \times \sqrt{2} }{3 \times \sqrt{2} } \\ = \frac{4}{3}$