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Juliette [100K]
3 years ago
13

Help me plz......................

Mathematics
1 answer:
alex41 [277]3 years ago
4 0
The picture has the answer and here are the calculations:

62 X 9 = 558

62 X 4 = 248

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Which pair of addenda has sun of 0?
alexandr402 [8]

Answer:

-5 and 5.

Step-by-step explanation:

Subtracting 5 from 5, leads to 0 as the final answer.

I hope this  helps! :)

7 0
2 years ago
Read 2 more answers
Derek's math teacher put some candy in a brown paper bag. The bag contains 4 lemon, 6 lime, 8 cherry, 2 pineapple, 5 orange, and
kolbaska11 [484]

Answer:

Even though 14 candies were gone there still is a very low change of getting pineapple. out of 12 candies 2 are pineapple.

Step-by-step explanation:

5 0
3 years ago
Syracuse and New York City are 240 miles apart. One car left Syracuse heading for New York City at an average of 65 mph. A secon
bazaltina [42]
Let x be the distance from Syracuse where they pass. The first car travels a distance of x in time x/65 while the second car travels a distance 240-x in time (240-x)/55. They pass at the same time after leaving their starting points so x/65=(240-x)/55.
Cross-multiplying we get: 55x=65(240-x)=15600-65x, 120x=15600, x=15600/120=130 miles.
They pass 130 miles from Syracuse.
6 0
3 years ago
Find the difference. express the answer in scientific notation. (5.29 times 10 superscript 11 baseline) minus (3.86 times 10 sup
Georgia [21]

The difference between (5.29 times 10 superscript 11 baseline) minus (3.86 times 10 superscript 11 baseline) is 1. 43 × 10^11

<h3>How to determine the notation</h3>

Given the expression

(5. 29 × 10^11) - (3. 86 × 10 ^11)

First, find the common factor

10^11 ( 5. 29 - 3. 86)

Then substract the values within the bracket

10^11 (1. 43)

Multiply with the factor, we have

⇒1. 43 × 10^11

Thus, the difference between (5.29 times 10 superscript 11 baseline) minus (3.86 times 10 superscript 11 baseline) is 1. 43 × 10^11

Learn more about index notation here:

brainly.com/question/10339517

#SPJ1

7 0
1 year ago
A 4 metre ladder is placed against a vertical wall.
Black_prince [1.1K]

Answer:

Original position: base is 1.5 meters away from the wall and the vertical distance from the top end to the ground let it be y and length of the ladder be L.

Step-by-step explanation:

By pythagorean theorem, L^2=y^2+(1.5)^2=y^2+2.25 Eq1.

Final position: base is 2 meters away, and the vertical distance from top end to the ground is y - 0.25 because it falls down the wall 0.25 meters and length of the ladder is also L.

By pythagorean theorem, L^2=(y -0.25)^2+(2)^2=y^2–0.5y+ 0.0625+4=y^2–0.5y+4.0625 Eq 2.

Equating both Eq 1 and Eq 2: y^2+2.25=y^2–0.5y+4.0625

y^2-y^2+0.5y+2.25–4.0625=0

0.5y- 1.8125=0

0.5y=1.8125

y=1.8125/0.5= 3.625

Using Eq 1: L^2=(3.625)^2+2.25=15.390625, L=(15.390625)^1/2= 3.92 meters length of ladder

Using Eq 2: L^2=(3.625)^2–0.5(3.625)+4.0625

L^2=13.140625–0.90625+4.0615=15.390625

L= (15.390625)^1/2= 3.92 meters length of ladder

<em>hope it helps...</em>

<em>correct me if I'm wrong...</em>

4 0
3 years ago
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