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sertanlavr [38]
3 years ago
9

What number should be added to 77 to make the sum 0?

Mathematics
2 answers:
Lina20 [59]3 years ago
6 0

77 + x = 0

so x = -77

AlexFokin [52]3 years ago
6 0
77 should be multiplied by 0 to get 0<span />
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(Four-fifths + three-fifths) + 3.5 times 5
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Answer:

18.9

Step-by-step explanation:

First, lets solve for the fractions. You can divide the fractions from the top, to their bottom (4 divided by 5, 3 divided by 5), in this case, you get 1.4. Now you have to rewrite the problem: 1.4+3.5x5. You solve it, and get 18.9.

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Percent means parts out of 100
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\qquad \qquad\huge \underline{\boxed{\sf Answer}}

Let's solve ~

\qquad \sf  \dashrightarrow \: (x {}^{3}  - 4x {}^{2}  + 1) + (3 {x}^{2}  + x)

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\qquad \sf  \dashrightarrow \:  {x}^{3}  - 4 {x}^{2}  + 3x {}^{2}  + x + 1

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A certain car rental location charges a daily fee as well as a mileage charge. On one trip a businessman rented a car for the da
nikklg [1K]

Answer:

x\approx 267\ miles

Step-by-step explanation:

<u>Linear Modeling</u>

Some events can be modeled as linear functions. If we are in a situation where a linear model is suitable, then we need two sample points to make the model and predict unknown behaviors.

The linear function can be expressed in the slope-intercept format:

f(x)=mx+b

For the problem at hand, we must pick the adequate variables according to the data provided.

The question states the charge for renting a car is a function of the mileage. It also provides two points from which we can build our model. Let's set the following variables:

c = the charge for renting a car in dollars

x = the distance driven by the businessman in miles

Representing the ordered pair as (x,c), we have the points: (150,79) and (65,63.70). Our model will be expressed as:

c = mx+b

We must find the values of m and b with the data provided. Substituting the first point:

79 = 150m+b

Substituting the second point:

63.70 = 65m+b

Both equations form the following system:

\left\{\begin{matrix}150m+b=79\\ 65m+b=63.70 \end{matrix}\right.

Subtracting both equations:

150m-65m=79-63.70

Note the variable b was canceled out in the operation, leaving only the variable m to solve. Joining like terms:

85m=15.3

Solving:

m=15.3/85=0.18

From the first equation

79 = 150m+b

Solving for b:

b=79-150m=79-150(0.18) = 52.

The model for the problem is:

c=0.18x+52

Now we need to calculate how many miles (x) could be driven for c=$100. From the equation above, substitute c=100

100=0.18x+52

Solve for x:

0.18x+52=100

0.18x=100-52=48

x=48/0.18=266.67

Rounding to the closest integer:

\boxed{x\approx 267\ miles}

7 0
3 years ago
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