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n200080 [17]
3 years ago
8

6 1/2 divided by 3 2/3

Mathematics
2 answers:
iris [78.8K]3 years ago
8 0

Answer:

39/22 = 1 17/22

Step-by-step explanation:

Attached below :

I hope im right!!

Novay_Z [31]3 years ago
3 0
1 1/2 !!! here you go
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I NEED HELP FAST what is y+1=5/6(x-2) in standard form?
Irina18 [472]

Answer:

\large\boxed{5x-6y=16}

Step-by-step explanation:

The standard form of an equation of a line:

Ax+By=C

We have the equation in the point-slope form. Convert:

y+1=\dfrac{5}{6}(x-2)\qquad\text{multiply both sides by 6}\\\\6y+6=6\!\!\!\!\diagup^1\cdot\dfrac{5}{6\!\!\!\!\diagup_1}(x-2)\\\\6y+6=5(x-2)\qquad\text{use the distributive property}\\\\6y+6=(5)(x)+(5)(-2)\\\\6y+6=5x-10\qquad\text{subtract 6 from both sides}\\\\6y+6-6=5x-10-6\\\\6y=5x-16\qquad\text{subtract}\ 5x\ \text{from both sides}\\\\-5x+6y=5x-5x-16\\\\-5x+6y=-16\qquad\text{change the signs}\\\\\boxed{5x-6y=16}

6 0
3 years ago
CAN SOMEONE PLEASE HELP ME!!!!
padilas [110]

Answer:

The third answer aka C

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Jackie scored 81 and 87 on her first two quizzes . Write and solve a compound inequality to find the possible values for a third
asambeis [7]

Answer:

The third score must be larger than or equal to 72, and smaller than or equal 87

Step-by-step explanation:

Let's name "x" the third quiz score for which we need to find the values to get the desired average.

Recalling that average grade for three quizzes is the addition of the values on each, divided by the number of quizzes (3), we have the following expression for the average:

average=\frac{81+87+x}{3}

SInce we want this average to be in between 80 and 85, we write the following double inequality using the symbols that include equal sign since we are requested the average to be between 80 and 85 inclusive:

80\leq average\leq 85\\80\leq \frac{81+87+x}{3} \leq 85\\80\leq \frac{168+x}{3} \leq 85

Now we can proceed to solve for the unknown "x" treating each inaquality at a time:

80\leq \frac{168+x}{3}\\3*80\leq 168+x\\240\leq 168+x\\240-168\leq x\\72\leq x

This inequality tells us that the score in the third quiz must be larger than or equal to 72.

Now we study the second inequality to find the other restriction on "x":

\frac{168+x}{3} \leq 85\\168+x\leq 85 *3\\168+x\leq 255\\x\leq 255-168\\x\leq 87

This ine72\leq x} \leq 87quality tells us that the score in the third test must be smaller than or equal to 87 to reach the goal.

Therefore to obtained the requested condition for the average, the third score must be larger than or equal to 72, and smaller than or equal 87:

4 0
3 years ago
SOMEONE HELP ME PLSSSSSSS
mr Goodwill [35]

Answer:

y = 8x

Step-by-step explanation:

hope this is what u need if not comment and I'll change it

<3

7 0
3 years ago
Can some one explain how to do this?
Delvig [45]

Answer:

see explanation

Step-by-step explanation:

Using the tangent and sine ratios in the right triangle EFG

tan60° = \frac{opposite}{adjacent} = \frac{FG}{EG} = \frac{28}{EG} ( multiply both sides by EG )

EG × tan60° = 28 ( divide both sides by tan60° )

EG = \frac{28}{tan60} ≈ 16.2 in ( to the nearest tenth )

--------------------------------------------------------------

sin60° = \frac{opposite}{hypotenuse} = \frac{FG}{EF} = \frac{28}{EF} ( multiply both sides by EF )

EF × sin60° = 28 ( divide both sides by sin60° )

EF = \frac{28}{sin60} ≈ 32.3 in ( to the nearest tenth )

3 0
3 years ago
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