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Gnoma [55]
3 years ago
8

(6x + 5) + (-3x + 7) ?

Mathematics
2 answers:
cestrela7 [59]3 years ago
5 0

Answer:

the answer should be 3(x+4)

Lina20 [59]3 years ago
3 0
6x+3x=7-5
18x=2
x=18/2
x=9
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The diameter of Circle terminates on the circumference of the circle at​ (3,0) and (3,−7).. Write the equation of the circle in
Verdich [7]

Step-by-step explanation:

that means the center of the circle is exactly in the middle between the 2 points.

and since both points have the same x value (so, the diameter here is a vertical line), it is ready to get the y value of the middle : (-7 - 0) / 2 = -3.5

so, the coordinates of the center are (3, -3.5).

and that makes the standard circle equation

(x - h)² + (y - k)² = r²

to

(x - 3)² + (y + 3.5)² = 3.5² = 12.25

as h, k are the coordinates of the center, and r is the radius (half the diameter).

7 0
2 years ago
Jack wants to share his candy with friends. Right now he has 4 1/3 pieces of chocolate. How many friends can he give 1/2 a candy
cricket20 [7]

Answer:

8 Friends

Step-by-step explanation:

First convert 4 1/3 to a mixed fraction

4 1/3 --> 13/3

Then divide by 1/2 to find how many friends per 1/2 candy bar with 13/3 candy bars

(13/3)/(1/2)

=(13*2)/(3*1)

=26/3

8.66667

Since you can't have 0.66667 of a person you get 8 friends to give candy to

3 0
3 years ago
10 points! please help!
kumpel [21]

Answer:

i think its the third one

Step-by-step explanation:

5 0
4 years ago
Read 2 more answers
A bag of marbles comes with 3 blue marbles, 2 red marbles, and 5 yellow marbles. What is the ratio of red to yellow?
xz_007 [3.2K]

Answer:

2:5

Step-by-step explanation:

Total marbles: 10

red: 2

yellow: 5

2:5

4 0
3 years ago
Without actual division prove that x4 +2x3 -2x2 +2x -3 is exactly divisible by<br> x2 +2x-3
Brut [27]

Answer:

Step-by-step explanation:                

\displaystyle\Large\boldsymbol{} x^4+2x^3-2x^2+2x-3= \\\\\\x^4+2x^2(x-1)+2x-\underbrace{2-1}_{-3}=  \\\\\\x^4-1+2x^2(x-1)+2x-2 = \\\\\\(x^2-1)(x^2+1)+2x^2(x-1)+2(x-1) = \\\\\\\underline{(x-1)}(x+1)(x^2+1)+2x^2\underline{(x-1)} +2\underline{(x-1)} =\\\\\\(x-1)((x+1)(x^2+1)+2x^2+2)=\\\\\\(x-1)(x^3+x^2+2x^2+x+2+1)=\\\\\\(x-1)(x^3+3x^2+x+3) =\\\\\\(x-1)( \underline{(x+3)}x^2+\underline{(x+3)})=(x^2+1)\underbrace{(x-1)(x+3)}_{x^2+2x-3}= \\\\\\(x^2+1)(x^2+2x-3) : (x^2+2x-3)=x^2+1

7 0
3 years ago
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