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2 years ago

2m-t=sm+5 you would have to find m

Mathematics

1 answer:

Ira Lisetskai [31]2 years ago

6 0

Answer:

m=5+t/2-s

Step-by-step explanation:

arrange like terms

2m-sm=5+t

factotise m in the first side of the equation

m(2-s)=5+t

divide both sides by (2-s)

therefore m=5+t/2-s

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Use this diagram to find the required measures. 1 = 30°, 2 = 30°, 3 =

crimeas [40]

Answer:

if thisa is a triangle then 180-30+30 = 120 degree and we say all angles on a triangle add up to 180

Then reaply the rule changing 180 to 360 on all 4 sided shapes

180(n-2) to all other shapes.

ie) pentagon 180(n-2) = 540

continue with 540-30-30 = 480 etc....

Step-by-step explanation:

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2 years ago

What is the area of a square when the side length is 2/3cm

Leviafan [203]

$\bf \textit{area of a square}\\\\ A=s^2~~ \begin{cases} s=length~of\\ \qquad a~side\\[-0.5em] \hrulefill\\ s=\frac{2}{3} \end{cases}\implies A=\left( \cfrac{2}{3} \right)^2\implies A=\cfrac{2^2}{3^2}\implies A=\cfrac{4}{9}$

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3 years ago

Omae wa sinderou nani (questions in the image btw)

Korvikt [17]

Let $a$ be the number of hours worked at Job A and $b$ the number of hours at Job B. Then

$a+b=30$

and

$7.5a+8b=234.50$

From the first equation,

$b=30-a$

and substituting this into the second gives

$7.5a+8(30-a)=234.50\implies-0.5a+240=234.50$

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3 years ago

Someone answer. Will give brainlest

Leto [7]

Area inside the semi-circle and outside the triangle is (91.125π - 120) in²

Solution:

Base of the triangle = 10 in

Height of the triangle = 24 in

Area of the triangle = $\frac{1}{2} bh$

$$=\frac{1}{2} \times 10\times24$

Area of the triangle = 120 in²

Using Pythagoras theorem,

$\text{Hypotenuse}^2=\text{base}^2+\text{height}^2$

$\text{Hypotenuse}^2=10^2+24^2$

$\text{Hypotenuse}^2=100+576$

$\text{Hypotenuse}^2=676$

Taking square root on both sides, we get

Hypotenuse = 23 inch = diameter

Radius = 23 ÷ 2 = 11.5 in

Area of the semi-circle = $\frac{1}{2}\pi r^2$

$$=\frac{1}{2} \pi \times (13.5)^2$

Area of the semi-circle = 91.125π in²

Area of the shaded portion = (91.125π - 120) in²

Area inside the semi-circle and outside the triangle is (91.125π - 120) in².

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2 years ago

An isosceles triangle has an angle that measures 140°. Which other angles could be in that isosceles triangle? Choose all that a

lara [203]

Every triangle is 180 degrees, so each other angle should have 20

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2 years ago