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3 years ago

6

Anybody know the answer ? Please help :(

1 answer:

tiny-mole [99]3 years ago

6 0

Answer:

A. y= -2x+6

Step-by-step explanation:

The intercept is at 6, to make the line, you go down 2, over 1.

// have a great day //

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Can you answer these please many thanks

givi [52]

Given: (a) $2(x+3)=2x+6$ and (b) $4(y-3)=4y-12$ .

To find: The expanded form of the given expressions.

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(d) $3(5-q)=15-3q$ (using $a(b-c)=ab-ac$ )

(e) $5(2c+1)=10c+5$ (using $a(b+c)=ab+ac$ )

(f) $3(2x-5)=6x-15$ (using $a(b-c)=ab-ac$ )

(g) $7(4b-1)=28b-7$ (using $a(b-c)=ab-ac$ )

(h) $3(2x+y-5)=3((2x+y)-5)$

⇒ $3(2x+y-5)=3(2x+y)-15$ (using $a(b-c)=ab-ac$ )

⇒ $3(2x+y-5)=6x+3y-15$ (using $a(b+c)=ab+ac$ )

(i) $2(6a-4b+3)=2((6a-4b)+3)$

⇒ $2(6a-4b+3)=2(6a-4b)+6$ (using $a(b+c)=ab+ac$ )

⇒ $2(6a-4b+3)=12a-8b+6$ (using $a(b-c)=ab-ac$ )

(j) $6(m+n+p)=6((m+n)+p)$

⇒ $6(m+n+p)=6(m+n)+6p$ (using $a(b+c)=ab+ac$ )

⇒ $6(m+n+p)=6m+6n+6p$ (using $a(b+c)=ab+ac$ )

(k) $y(y+2)=y^2+2y$ (using $a(b+c)=ab+ac$ )

(l) $g(g-3)=g^2-3g$ (using $a(b-c)=ab-ac$ )

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(n) $a(b+c)=ab+ac$ (using $a(b+c)=ab+ac$ )

(o) $s(3s-4)=3s^2-4s$ (using $a(b-c)=ab-ac$ )

(p) $2x(x+5)=2x^2+10x$ (using $a(b+c)=ab+ac$ )

(q) $4y(x-3)=4xy-12y$ (using $a(b-c)=ab-ac$ )

(r) $5a(2b-5)=10ab-25a$ (using $a(b-c)=ab-ac$ )

(s) $4a(3b+2c)=12ab+8ac$ (using $a(b+c)=ab+ac$ )

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6 0

3 years ago

A chain fits tightly around two gears as shown. What is the radius of the smaller gear? Round your answer to the nearest tenth.

GrogVix [38]

Using the Pythagorean theorem we can solve for the radius

see attached picture:

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2 years ago

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Vlad [161]

<u>Answer</u>:

equation: y = x/2

<u>Explanation</u>:

let the points be (-6, -3) , ( 0, 0)

slope: $\frac{y2-y1}{x2-x1}$

: $\frac{0--3}{0--6}$

: $\frac{1}{2}$

Equation using:

y - y1 = m ( x - x1 )

y - - 3 = 1/2( x - - 6 )

y + 3 = x/2 + 3

$y\\$ = $\frac{x}{2}$

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2 years ago

If a rectangle JKLM, JK is equal to 12 feet, and LN is equal to 6.5 feet, find KM

Rus_ich [418]

12.5 feet is the answer.

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3 years ago

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The graph of f(x)=ax^2 is narrower than the graph of g(x)=dx^2 when a<d

Lynna [10]

Answer:

Step-by-step explanation:

as given in question that a > 0 so

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3 years ago