So work it out as 0.25x4 =£1
Then 4-1=£3
£3 / 0.30 =10
10+4
So it is 14 days late
        
             
        
        
        
The gcf of 25 and 14 would be 2
        
                    
             
        
        
        
First, find the slope of the line thru these 2 pts:
         5-4
m = --------- = -1/2
         2 -4 
Use the slope-intercept formula y = mx + b:
5 = (-1/2)(2) + b.  Then the y-intercept is 5 + 1, or 6:  y = (-1/2)x + 6
Multiplying this entire result (3 terms) by 2 results in 2y = -x + 12, or
x + 2y = 12 (answer)
        
             
        
        
        
Answer:
Q1)  7/8
Q2) 1/2
Q3) (-3)
Q4) 1
Step-by-step explanation:
(-2,-2) (-10,-9)
slope = (y₂ - y₁)/(x₂-x₁)
           =  (-9 -{-2}) / (-10-{-2})
            = (-9+2)/(-10+2) = -7/-8
           = 7/8
Q2) Slope= (-2+4)/7-3 = 2/4 = 1/2
Q3) slope = (4-10)/(-1+3) = -6/2 = (-3)
Q4) slope = (0+2)/(-1+3) = 2/2 = 1
 
        
             
        
        
        
Answer:
We conclude that there is no change in the average weight since the implementation of a new breakfast and lunch program at the school.
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 100 pounds
Sample mean,  = 98 pounds
 = 98 pounds
Sample size, n = 35
Alpha, α = 0.05
Population standard deviation, σ = 7.5 pounds
First, we design the null and the alternate hypothesis
 
We use one-tailed(left) z test to perform this hypothesis.
Formula:
 
Putting all the values, we have
 
Now,  
We calculate the p-value with the help of standard normal table.
P-value = 0.057398
Since the p-value is greater than the significance level, we fail to reject the null hypothesis and accept is.
We conclude that there is no change in the average weight since the implementation of a new breakfast and lunch program at the school.