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laila [671]
3 years ago
11

write an equation of the line which has the given slope and passes through the given point. m=-5; (9,1) with formula

Mathematics
1 answer:
omeli [17]3 years ago
6 0
If the slope is -5, the line will be in the form y=-5x+b.  Substituting 9, 1 for x and y respectively, we see that 1=b-45, so b=46.  Therefore, the equation is y=-5x+46.
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consider quadrilateral ABCD as graphed above. rotate ABCD 90° clockwise about the origin, then dilate with a scale factor of 3/2
saw5 [17]

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5 0
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Read 2 more answers
Help me please with some of my math homework I don’t really understand what p is equal to
horrorfan [7]

The value of p is 5.

<u>Step-by-step explanation</u>:

<u>step 1</u> : The given expression is -6( p -5 )

<u>step 2</u> : To find any unknown value in an expression, equate it to zero.

<u>step 3</u> : -6( p -5 ) = 0

<u>step 4</u> : Multiply -6 to each term in the bracket.

            -6p + 30 = 0

            -6p = -30

              p = -30/-6

              p = 5

8 0
2 years ago
Hey Mahfia, please help! Find an equation in standard form for the hyperbola with vertices at (0, ±10) and asymptotes at
Dafna1 [17]

Answer:

\huge\boxed{  \red{ \boxed{ \tt{ \frac{ {y}^{2} }{ {10}^{2} }  -  \frac{ {x}^{2} }{ {12}^{2} }  = 1}}}}

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • conic sections
  • PEMDAS
<h3>tips and formulas:</h3>
  • \sf hyperbola \:equation :  \\  \sf  \frac{ {x}^{2} }{ {a}^{2} }   -  \frac{ {y}^{2} }{ {b}^{2} }  = 1
  • vertices of hyperbola:(±a,0) and (0,±b) if reversed
  • \sf \: asymptotes :  \\ y =   \pm\frac{b}{a} x
<h3>given:</h3>
  • vertices: (0,±10)
  • the hyperbola equation is inversed since the vertices is (0,±10)
  • asymptotes:\pm \frac{5}{6}x
<h3>let's solve:</h3>
  • the asymptotes are in simplest and we know b is ±10

according to the question

  1. y =  \sf  \frac{5 \times 2}{6 \times 2} x \\ y =  \frac{10}{12} x

therefore we got

  • a=12
  • b=10

note: the equation will be inversed

let's create the equation:

  1. \sf substitute \: the \: value \: of \: a \: and \: b :  \\  \sf  \frac{ {y}^{2} }{ {10}^{2} }  -  \frac{ {x}^{2} }{ {12}^{2} }  = 1

3 0
3 years ago
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