3 years ago

write an equation of the line which has the given slope and passes through the given point. m=-5; (9,1) with formula

1 answer:

6 0

If the slope is -5, the line will be in the form y=-5x+b. Substituting 9, 1 for x and y respectively, we see that 1=b-45, so b=46. Therefore, the equation is y=-5x+46.

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Please answer correctly !!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!

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Answer:

-10

Step-by-step explanation:

-(x-5) ^2+25

-x+5^2+25

-5 -5

-x^2+20

-2x+20

---- ----

-2 -2

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The table below shows the account value of each of Dmitri's three bank accounts

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Answer:

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Step-by-step explanation:

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Which of the following symbols will make a true sentence when inserted in the blank? 4/15___0.26

Sauron [17]

Answer:D

Step-by-stepA explanation: if you simply the fraction by 4/15. The answer is 0.26

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3 years ago

You invest $1000 in a 5-year savings bond that pays 8% annual interest on the principal. How much total interest will you have e

atroni [7]

8% of 1000 = 80
8% of 1080 = 86.4
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3 0

3 years ago

A dog owner observes that from birth to age 14 weeks, the puppy’s weight can be modelled by the equation w=365×(1.23)t , for (0≤

Fantom [35]

Answer and Step-by-step explanation:

(1) Scale factor is a constant value that multiplies another value. For a puppy's weight, scale factor is 1.23.

The percentage growth is

1.23 = 1 + 0.23

Percentage is 0.23 or 23%.

(2) Equation for increase is

$w=365(1.23)^{t}$

When w = 4000g:

$4000=365(1.23)^{t}$

$(1.23)^{t}=\frac{4000}{365}$

$1.23^{t}=10.96$

Using the log law:

$log_{b} (M^{k}) = klog_{b}(M)$

$log(1.23^{t})=log(10.96)$

t.log(1.23) = log(10.96)

0.08990t = log(10.96)

$t=\frac{log10.96}{0.08990}$

t = 11.56

The puppy will weigh 4000 grams in 11 and half weeks or between 11 and 12 weeks.

5 0

3 years ago