We have been given two points.
and
. We are asked to find the point B such that it divides line segment AC so that the ratio of AB to BC is 4:1.
We will use segment formula to solve our given problem.
When a point P divides segment any segment internally in the ratio
, then coordinates of point P are:
![[\right x=\frac{mx_2+nx_1}{m+n},y=\frac{my_2+ny_1}{m+n}\left]](https://tex.z-dn.net/?f=%5B%5Cright%20x%3D%5Cfrac%7Bmx_2%2Bnx_1%7D%7Bm%2Bn%7D%2Cy%3D%5Cfrac%7Bmy_2%2Bny_1%7D%7Bm%2Bn%7D%5Cleft%5D)
and
.

Upon substituting our given information in above formula, we will get:
![[\right x=\frac{4(3)+1(3)}{4+1},y=\frac{4(9)+1(4)}{4+1}\left]](https://tex.z-dn.net/?f=%5B%5Cright%20x%3D%5Cfrac%7B4%283%29%2B1%283%29%7D%7B4%2B1%7D%2Cy%3D%5Cfrac%7B4%289%29%2B1%284%29%7D%7B4%2B1%7D%5Cleft%5D)
![[\right x=\frac{12+3}{5},y=\frac{36+4}{5}\left]](https://tex.z-dn.net/?f=%5B%5Cright%20x%3D%5Cfrac%7B12%2B3%7D%7B5%7D%2Cy%3D%5Cfrac%7B36%2B4%7D%7B5%7D%5Cleft%5D)
![[\right x=\frac{15}{5},y=\frac{40}{5}\left]](https://tex.z-dn.net/?f=%5B%5Cright%20x%3D%5Cfrac%7B15%7D%7B5%7D%2Cy%3D%5Cfrac%7B40%7D%7B5%7D%5Cleft%5D)
![[\right x=3,y=8\left]](https://tex.z-dn.net/?f=%5B%5Cright%20x%3D3%2Cy%3D8%5Cleft%5D)
Therefore, the coordinates of point B would be
.
Answer:
3x+12
Step-by-step explanation:
You need to do 3 times x which equals 3x and then do 3 times 4 and get 12 so it ends up as 3x+12
hope this helps
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The answer 300 seconds/5 minutes

Let's find out the gradient (Slope " m ") of line q ;



Now, since we already know the gradient let's find of the equation of line by using its Slope and one of the points using point slope form of line :


Now, plug in the value of gradient ~

here we can clearly observe that, the Area under the curve can easily be represented as :

Since, all the values of y that lies in the shaded region is smaller than the actual value of y for the corresponding values of x in the equation of line q
Answer:
36 cm2
Step-by-step explanation:
tep-by-Step:
Start with the formula:
Area = a2
Don't forget: a2 = a × a (a squared).
Substitute the side length into the formula. In our example, a = 6.
Area = 6^2 = 6 × 6 = 36 cm2
Answer:
The area of the square with sides of length 6 cm is 36 cm2.