Let Ch and C denote the events of a student receiving an A in <u>ch</u>emistry or <u>c</u>alculus, respectively. We're given that
P(Ch) = 88/520
P(C) = 76/520
P(Ch and C) = 31/520
and we want to find P(Ch or C).
Using the inclusion/exclusion principle, we have
P(Ch or C) = P(Ch) + P(C) - P(Ch and C)
P(Ch or C) = 88/520 + 76/520 - 31/520
P(Ch or C) = 133/520
Answer:
yes
Step-by-step explanation:
Answer:
Rate in relationship A = (6 - 3)/(8 - 4) = 3/4 = 0.75
For Table A: Rate = (3 - 1.2)/(5 - 2) = 1.8/3 = 0.6
For table B: Rate = (3.5 - 1.4)/(5 - 2) = 2.1/3 = 0.7
For table C: Rate = (4 - 1.6)/(5 - 2) = 2.4/3 = 0.8
For table D: Rate = (2 - 1.5)/(4 - 3) = 0.5/1 = 0.5
Therefore, the correct answer is option C.
Answer:
1/5 hours i.e 0.2 hours (which is 12 mins)
Step-by-step explanation:
First note that 12 1/2 = 12.5, and 2 1/2 = 2.5.
To work out how many hours it takes hime to drive one mile, we divide the number of hours (2.5) by the number of miles (12.5),
i.e 2.5 ÷ 12.5
which equals 1/5 = 0.2 hours (= 12 mins).
Step-by-step explanation:
Part A, Option 1 is a exponential function while option is a linear equation.
Part B, Let y=b*a^(x) be the function for option 1. At x=1, y=1100 and at x=2, y=1210. 1100=b*a and 1210=b*a^2. Dividing them both we get, b=1.1 and a=1000. y=1000*(1.1)^(x). For option 2, it's a linear equation with a function y(x)=1000+100x.
The 20 year difference would be immense. With option 1, Belinda will get $6727.5 whereas with option 2, they will end up with $3000
