In the early months of some year, one site added 0.2 million new accounts every day. at this rate, how many days would be need
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Linear programming which shows the best investment strategy for the client is Max Z=0.12I +0.09B and subject to constraints are :I+ B<=25000,
0.005 I +0.004B<=250.
Given maximum investment client can make is $55000, annual return= 9%, The investment advisor requires that at most $25,000 of the client's funds should be invested in the internet fund. The internet fund, which is the more risky of the two investment alternatives, has a risk rating of 5 per thousand dollars invested. the blue chip fund has a risk rating of 4 per thousand dollars invested.
We have to make a linear programming problem.
Let
I= Internet fund investment in thousands.
B=Blue chip fund investment in thousands.
Objective function:
Max Z=0.12I+0.09B
subject to following constraints:
Investment amount: I+ B<=25000
Risk Rating: 5/100* I+4/100*B<=250 or 0.005 I +0.004B<=250
I,B>=0.
Hence the objective function is Max Z=0.12 I+ 0.09 B.
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Answer:
y = x - 12
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = - x ← is in slope- intercept form
with slope m = - , c = 0
Given a line with slope m then the slope of a line perpendicular to it is
= -
= -
=
, then
y = x + c ← is the partial equation
To find c substitute (3, - 8) into the partial equation
- 8 = 4 + c ⇒ c = - 8 - 4 = - 12
y = x - 12 ← equation of perpendicular line