Answer:

Step-by-step explanation:
Let
represent students playing basketball,
represent students playing baseball.
Then,
, 
Let
be the total number of students. So,
.
Now,


3 students play neither of the sport. So, students playing either of the two sports is given as:

∴ 
From the probability addition theorem,

Where,
is the probability that a student chosen randomly from the class plays both basketball and baseball.
Plug in all the values and solve for
. This gives,

Therefore, the probability that a student chosen randomly from the class plays both basketball and baseball is 
60
30 *2
15 * 2 * 2
5 * 3 * 2 * 2
Answer:
4÷68=1/17 is correct answer
Answer:
129 - 280 = 51.. So the answer is 51%
Answer:
m=(-5y-3y)
Step-by-step explanation:
5m+5y=4m-3y
5m-4m=-5y-3y
m(5-4)=-5y-3y
m=(-5y-3y)/1