Answer:
Step-by-step explanation:
We would use the t- distribution.
From the information given,
Mean, μ = 2950
Standard deviation, σ = 115
number of sample, n = 25
Degree of freedom, (df) = 25 - 1 = 24
Alpha level,α = (1 - confidence level)/2
α = (1 - 0.98)/2 = 0.01
We will look at the t distribution table for values corresponding to (df) = 24 and α = 0.01
The corresponding z score is 2.492
We will apply the formula
Confidence interval
= mean ± z ×standard deviation/√n
It becomes
2950 ± 2.492 × 115/√25
= 2950 ± 2.492 × 23
= 2950 ± 57.316
The lower end of the confidence interval is 2950 - 57.316 =2892.68
The upper end of the confidence interval is 2950 + 57.316 = 3007.32
The solution is correct.
Answer:
$ 6,189.18
Step-by-step explanation:
From the above question, we can deduce that we are meant to find the Principal (Initial Amount ) invested.
The formula for the Principal of a compound interest that is compounded continuously is given as:
P = A / e^rt
Where
P = Principal
A = Totally Amount after time t = $11,300
r = Interest rate = 4.3 % = 0.043
t = 14 years
P = $11,300/ e ^0.043 × 14
P = $ 6,189.18
Hence, Landon needs to invest, $ 6,189.18
Y=4x because 20/5 equals 4
The answer would be B because the 100 stays in there and you are adding 8% per year. Hope this helps.
Answer:
the solution is the whole line y = -x + 7
Step-by-step explanation:
both equations are identical
2y = 14 - 2x
=> y = 7 - x
which is exactly the same information as y=-x+7
so, there is no single crossing point. they are exactly covering each other. what "remains" is simply the whole line.
