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guajiro [1.7K]
3 years ago
7

The axis of symmetry for the graph of the function f(x) = 3x2 + bx + 4 is x = . What is the value of b?

Mathematics
2 answers:
photoshop1234 [79]3 years ago
6 0
The value of b is one. You just have to use the standard equation y = a + bx^2 + c. Get a, b, then c and from the given equation above you can derive a formula which is x is equal to the - b over 2 multiplied by a. if you get the value of x then substitute it to the equation and you will now get the value of b.
Mila [183]3 years ago
3 0

Answer:

b = ±i

Step-by-step explanation:

Given the axis of symmetry of the equation f(x) = 3x²+bx+4 is x= b, to get the value of b we will substitute x = b into the equation and equate to zero as shown:

at f(b) = 0

f(b) = 3b² + b(b) + 4 = 0

3b²+b² + 4 = 0

4b² = -4

b² = -4/4

b² = -1

b = √-1

b = ±i

The value of b is a complex number ±i

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Solve question 10 using substitution or elimination. Show all work.
BlackZzzverrR [31]
Solid paper costs 1.75 each
Printed paper costs 2.50 each

Given:
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Joel = $51.50 (8 rolls solid paper and 15 rolls of
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8x = 51.50 - 15y
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Substitute X:
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12(51.50 - 15y)/8 + 9y = 43.50
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Y= 2.50

x = (51.50 - 15y)/8
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Hope that helps! Have a good day :)
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2 years ago
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3 years ago
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Andreyy89

Answer: A

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As you can see, the triangles only slide to the right side, along the x axis. Therefore, we can eliminate B and C.

Now, we can see that the triangle has shifted by +8 units. Therefore, A is the correct answer.

7 0
3 years ago
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