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olya-2409 [2.1K]
2 years ago
15

The image shows a circle centered at point O angle AOB Measures at 42 degrees.

Mathematics
1 answer:
trasher [3.6K]2 years ago
7 0

The measure of angle ACB for circle centered at point O is 21°

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

∠AOB = 2 * ∠ACB (angle at center is twice the angle at circumference)

42 = 2 * ∠ACB

∠ACB = 21°

The measure of angle ACB for circle centered at point O is 21°

Find out more on equation at: brainly.com/question/2972832

#SPJ1

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Answer:

3,312

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Plzz hellp :( i will mark you the brainlist if some on helps (A rectangular prism has a length of 1 1/4 yards, a width of 2 1/2
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V=1 \frac{1}{4} * 2 \frac{1}{2} *4 \\  \\ &#10;V=  \frac{5}{4}* \frac{5}{2}*4 \\  \\ &#10;V= \frac{25}{2} \\  \\ &#10;V=12 \frac{1}{2}

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4 0
3 years ago
Find m/KMN. L 60° K 1⁰40 6x (11x+15)° N​
miskamm [114]

Answer:

  114°

Step-by-step explanation:

The exterior angle is the sum of the remote interior angles.

__

<h3>setup</h3>

  (11x +15)° = 60° +6x°

<h3>solution</h3>

  5x = 45 . . . . . . . . . divide by °, subtract 15+6x

  x = 9 . . . . . . . . . . divide by 5

The measure of exterior angle KMN is ...

  m∠KMN = (11(9) +15)° = 114°

_____

<em>Additional comment</em>

Both the sum of interior angles and the sum of angles of a linear pair are 180°. If M represents the interior angle at vertex M, then we have ...

  60° +6x° +M = 180°

  (11x +15)° +M = 180°

Equating these expressions for 180° and subtracting M gives the relation we used above:

  (11x +15)° +M = 60° +6x° +M . . . . . equate the two expressions for 180°

  (11x +15)° = 60° +6x° . . . . . . . . . . . subtract M

This is also described by "supplements to the same angle are equal."

4 0
2 years ago
Read 2 more answers
Increase 14187.13 by 4.5%
Ksivusya [100]
If you increase a number by 4.5%, then you're adding 4.5% of that number to 100% of that number. So essentially you just multiply 14187.13 by 104.5%, or 1.045 to find the answer, which is 14,825.55.
7 0
3 years ago
A path 2.5m wide is running outside a square field whose side is 45m. Determine the area of the path.
aliya0001 [1]

Answer:

The area of the path would be 231.25 squared meters.

Step-by-step explanation:

Consider the path as 45m (the field's area), then add 2.5m to all of the sides. You'll get 47.5m on all sides. Then you do 47.5² to get 2256.25 squared meters. After that, you'll remove the area of the squared field. To do this, do 45m². By doing this, you'll get 2025 squared meters. Lastly, to finish up the question, do 2256.25 - 2025. This would get you 31.25 squared meters, the answer.

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