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brilliants [131]
3 years ago
13

The daily low temperatures in a city have been below 0° Fahrenheit (F) for the past two days. On Monday, the daily low temperatu

re was −2℉ and on Tuesday, the daily low temperature was −7℉. What is the absolute value of the change in daily low temperatures between these two days, in degrees Fahrenheit?
(This is math class btw)
Mathematics
1 answer:
ikadub [295]3 years ago
8 0

Answer:

5ºF is the absolute value of the change.

Step-by-step explanation:

Since absolute value is alwasy positive you will not need the negative sign. The difference between 7 and 2 is 5, so the answer is 5.

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Answer:

$x=\frac{\pi }{3}+2\pi n, n\in \mathbb{Z}$

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or

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Step-by-step explanation:

4\text{cos}^2(x)-1=0\\4\text{cos}^2(x)=1\\

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$cos(x)=\pm\frac{1}{2}  $

So, when cos(x) is equal to

$\frac{1}{2}   \text{ and } -\frac{1}{2}$    ?

For

$cos(x)=\frac{1}{2} $

We are talking about x = 60º and x = 300º, Quadrant I and IV, respectively. In radians:

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$\:x=\frac{5\pi }{3}+2\pi n, n \in \mathbb{Z}$

or

$x=\frac{\pi}{3}+\pi n, n \in \mathbb{Z} $

For

$cos(x)=-\frac{1}{2} $

We are talking about x = 120º and x = 240º, Quadrant II and III, respectively. In radians:

$x=\frac{2\pi }{3}+2\pi n, n\in \mathbb{Z}$

$\:x=\frac{4\pi }{3}+2\pi n, n \in \mathbb{Z}$

or

$x=\frac{2\pi }{3}+\pi n, n\in \mathbb{Z}$

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When I double my number add 4 and then subtract my number and subtract three I get my number plus one what is my number?
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