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Maru [420]
3 years ago
14

Plz help ,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,

Mathematics
1 answer:
Deffense [45]3 years ago
5 0
Hi I figured it out for you all you need to do is plug in the X factor .number 3 is y=-1
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What is the magnitude of the position vector whose terminal point is (-2, 4)?
zhuklara [117]

Answer:

  2√5

Step-by-step explanation:

The Pythagorean theorem tells you how to find the distance from the origin.

  d = √((-2)² +4²) = √20 = 2√5

The vector's magnitude is 2√5 ≈ 4.47214.

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3 years ago
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<img src="https://tex.z-dn.net/?f=y%20%3D%20%20%5Cfrac%7B%28190%29%5E%7B3%7D%20%7B68%5E%7B2%7D%20%7D%20%20%5Ctimes%20%28%20%5Cfr
mrs_skeptik [129]

Answer:

  \dfrac{\sqrt[3]{95^2}}{17\cdot95^4}=\dfrac{\sqrt[3]{9\,025}}{1\,384\,660\,625}

Step-by-step explanation:

The applicable rules of exponents are ...

  (ab)^c = (a^c)(b^c)

  (a^b)/(a^c) = a^(b-c)

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  \dfrac{190^3}{68^2}\times\dfrac{34}{95^{\frac{19}{3}}}=\dfrac{(2\cdot 95)^3}{(2\cdot 34)^2}\cdot\dfrac{34}{95^6\cdot 95^{\frac{1}{3}}}=2^{3-2}95^{3-6-\frac{1}{3}}34^{1-2}\\\\=2\cdot 95^{-3\frac{1}{3}}\cdot 34^{-1}=2\cdot 95^{-4+\frac{2}{3}}\cdot 34^{-1}\\\\=\dfrac{2\sqrt[3]{95^2}}{95^4\cdot 34}=\dfrac{\sqrt[3]{95^2}}{17\cdot95^4}\\\\=\dfrac{\sqrt[3]{9\,025}}{1\,384\,660\,625}

6 0
3 years ago
Please help, this is pretty important
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Answer:

C

Step-by-step explanation:

First, you need to rewrite the equation.

-3x+8y=12

8y=12+3x

y=3/2+3/8x

The slope is the coefficient of x, which is 3/8.

6 0
4 years ago
IK THIS LOOKS HARD BUT PLS HELO
skelet666 [1.2K]

Answer:

90

Step-by-step explanation:

formula = 1/3 x base area x height

1/3 x (9 x 2) x 15 = 90

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