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adoni [48]
3 years ago
12

In one minute,kayla can read 142 words.if she keeps this same rate, how many words can she read in 1 hour ???show your work

Mathematics
2 answers:
Anon25 [30]3 years ago
8 0

Answer:

8,760

Step-by-step explanation:

If Kaylah is reading 142 words in one minute, there is 60 minutes in an hour.

therefore,

142 x 60 = 8,760

Tamiku [17]3 years ago
4 0

Answer:

8520 minutes

Step-by-step explanation:

To solve, make a proportion

142 words in 1 minute, and x words in 60 minutes (1 hour).

142/1=x/60

Cross multiply

142*60=1*x

8520=x

Another way to solve is to know that each hour has 60 minutes, and she can read 142 words in 1 minute. So, we can just multiply 60 and 142.

60*142=8520

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the volume of a square shipping container is 15,625 cubic inches. Find the edge length of the shipping container
Llana [10]

Answer:

24.9 repeating in

Step-by-step explanation:

\sqrt[3]{15,625} = 24.9 repeating.

Basically, just find the cube root of 15,625. Since, the object is a cube, the volume formula is V=a^{3}. Just undo the a^{3} by finding the cube root. Hope this helps!!

7 0
3 years ago
A dairy farm uses the somatic cell count (SCC) report on the milk it provides to a processor as one way to monitor the health of
Eva8 [605]

Answer:

t=\frac{25000-210000}{\frac{37500}{\sqrt{5}}}=2.37  

p_v =P(t_{4}>2.37)=0.038  

If we compare the p value and a significance level assumed \alpha=0.1 we see that p_v so we can conclude that we reject the null hypothesis, and the actual true mean is higher than 210250 at 5% of significance.  

Step-by-step explanation:

Data given and notation

\bar X=250000 represent the sample mean  

s=37500 represent the standard deviation for the sample

n=5 sample size  

\mu_o =210250 represent the value that we want to test  

\alpha=0.1 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses to be tested  

We need to conduct a hypothesis in order to determine if the mean is higher than 210250, the system of hypothesis would be:  

Null hypothesis:\mu \leq 210250  

Alternative hypothesis:\mu > 210250  

Compute the test statistic  

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

We can replace in formula (1) the info given like this:  

t=\frac{25000-210000}{\frac{37500}{\sqrt{5}}}=2.37  

Now we need to find the degrees of freedom for the t distirbution given by:

df=n-1=5-1=4

Conclusion

Since is a one right tailed test the p value would be:  

p_v =P(t_{4}>2.37)=0.038  

If we compare the p value and a significance level assumed \alpha=0.1 we see that p_v so we can conclude that we reject the null hypothesis, and the actual true mean is higher than 210250 at 5% of significance.  

6 0
3 years ago
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Answer:

A) f (x) = -x^{2}- 3

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Graph B.
Because y< so shade underneath the line
And because it is less then not less than or equal to then the line is dashed.
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