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3 years ago

Find the missing values of x and y

Mathematics

1 answer:

Rasek [7]3 years ago

8 0

5x = 90° → x = 18°

9y = 90° → x = 10°

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1/2 (x-4/5)=3/5

malfutka [58]

1/2x-2/5=3/5 (BTW I got 2/5 by reducing 4/10)
1/2x=7/5 (BTW I got 7/5 by moving 2/5 to the other side)
Then do 7/5 times 2 and you get 14/5

14/5

I do free online math homework help tutoring if interested!

6 0

3 years ago

Mary has 36

morpeh [17]

Answer: i dont know if this is correct but i think the answer is.... tom will have 74 apples

Step-by-step explanation:

3 0

3 years ago

Write this as a power of 2. ex ( 2^n) requires knowledge of negative exponents

Snowcat [4.5K]

Answer:

Step-by-step explanation:

$\frac{32}{ \sqrt[8]{16} } \\$

Simplify

$\frac{32}{1.414213562} \\ \\ = 22.627417$

Method 2 :

By rationalizing the denominator

7 0

3 years ago

A diameter of a circle has enpoints (-2, 10) and (6, -4) in the standard (x, y) coordinate plane. What is the center of the circ

wlad13 [49]

Answer:

The center of the circle is $C(x,y) = (2, 3)$ .

Step-by-step explanation:

The center of the circle is the midpoint of the segment between the endpoints. We can determine the location of the center by this vectorial expression:

$C(x,y) = \frac{1}{2}\cdot R_{1}(x,y)+ \frac{1}{2}\cdot R_{2}(x,y)$ (1)

Where:

$C(x,y)$ - Center.

$R_{1} (x,y)$ , $R_{2} (x,y)$ - Location of the endpoints.

If we know that $R_{1} (x,y) = (-2,10)$ and $R_{2} (x,y) = (6,-4)$ , then the location of the center of the circle is:

$C(x,y) = \frac{1}{2}\cdot (-2,10)+\frac{1}{2}\cdot (6,-4)$

$C(x,y) = (-1, 5) + (3, -2)$

$C(x,y) = (2, 3)$

The center of the circle is $C(x,y) = (2, 3)$ .

8 0

3 years ago

How to find the constant of variation for the quadratic variation?

xeze [42]

Put the values you know in the formula and solve for the constant of variation.
.. y = kx^2
.. k = y/x^2 . . . . . fill in values for y and x and compute.

7 0

3 years ago