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Tanzania [10]
3 years ago
12

A quadratic function has x-intercepts 2 and 6 and its vertex is (4, 8). What is the corresponding quadratic expression? A. 2x2 −

16x + 24 B. -2x2 + 16x – 24 C. -2x2 - 16x + 24 D. -x2 − 16x + 12 E. -x2 − 16x – 24
Mathematics
1 answer:
Goryan [66]3 years ago
3 0

Given:

A quadratic function has x-intercepts 2 and 6 and its vertex is (4, 8).

To find:

The corresponding quadratic expression.

Solution:

If graph of a function intersect the x-axis at c, then (x-c) is a factor of the function.

A quadratic function has x-intercepts 2 and 6. It means (x-2) and (x-6) are two factors of the required quadratic function.

The function is defined as:

P(x)=a(x-2)(x-6)                    ...(i)

Where, a is a constant.

The vertex of the quadratic function is (4,8). It means the point (4,8) will satisfy the function.

Substituting x=4 and P(x)=8 in (i).

8=a(4-2)(4-6)

8=a(2)(-2)

8=-4a

Divide both sides by -4.

\dfrac{8}{-4}=a

-2=a

Putting a=-2 in (i), we get

P(x)=-2(x-2)(x-6)

P(x)=-2(x^2-6x-2x+12)

P(x)=-2(x^2-8x+12)

P(x)=-2x^2+16x-24

Therefore, the correct option is B.

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-4x - 6y = 6<br> 4x + 6y = -4
Sloan [31]

Step-by-step explanation:

-4x - 6y = 6

4x + 6y = -4

To solve a system of equations, we can add the two equations and solve for one of the remaining variables -- let's try to eliminate the x variable when we add the two equations together.

Right now, there's a -4x term in the first equation, and a 4x term in the second equation, so if we add those together, we'll be able to eliminate the x variable altogether and solve for y.

However, when we also have a -6y term in the first equation and 6y term in the second equation, so adding these together will also eliminate the y term, leaving a 0 on the left-hand side of the equation.

If we add the two numbers on the right side of the equation, we get -2, which does not equal 0, meaning there are no solutions to this system of equations.

3 0
3 years ago
Read 2 more answers
Match each equation with its solution set. Tiles a2 − 9a + 14 = 0 a2 + 9a + 14 = 0 a2 + 3a − 10 = 0 a2 + 5a − 14 = 0 a2 − 5a − 1
sattari [20]
We have that

N 1)
a²<span> − 9a + 14 = 0 
</span>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² − 9a)=-14

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² − 9a+20.25)=-14+20.25

Rewrite as perfect squares

(a-4.5)²=6.25--------> (a-4.5)=(+/-)√6.25

a1=4.5+√6.25-----> a1=7

a2=4.5-√6.25-----> a2=2

the solution problem N 1 is the pair {7, 2}


N 2) 

a²<span> + 9a + 14 = 0
</span>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² + 9a)=-14

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² +9a+20.25)=-14+20.25

Rewrite as perfect squares

(a+4.5)²=6.25--------> (a+4.5)=(+/-)√6.25

a1=-4.5+√6.25-----> a1=-2

a2=-4.5-√6.25-----> a2=-7

the solution problem N 2 is the pair {-2,-7}

N 3) 

a² + 3a − 10 = 0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² + 3a)=10

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² + 3a+2.25)=10+2.25

Rewrite as perfect squares

(a+1.5)²=12.25------> (a+1.5)=(+/-)√12.25

a1=-1.5+√12.25-----> a1=2

a2=-1.5-√12.25-----> a2=-5

the solution problem N 3 is the pair {2, -5}


N 4)

a²<span> + 5a − 14 = 0
</span>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² + 5a) =14

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² + 5a+6.25) =14+6.25

Rewrite as perfect squares

(a+2.5)² =20.25-------> (a+2.5)=(+/-)√20.25

a1=-2.5+√20.25-----> a1=2

a2=-2.5-√20.25-----> a2=-7

the solution problem N 4 is the pair {2, -7}


N 5) 

a² − 5a − 14 = 0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² − 5a)=14

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² − 5a+6.25)=14+6.25

Rewrite as perfect squares

(a-2.5)²=2025--------> (a-2.5)=(+/-)√20.25

a1=2.5+√20.25-----> a1=7

a2=2.5-√20.25-----> a2=-2

the solution problem N 5 is the pair {7, -2}

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3 years ago
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BRAINLIEST FOR BEST ANSWER
Temka [501]

Answer:

Option C is correct

The coordinate of C' or the transformed point of C is (-6, 5)

Step-by-step explanation:

From the given graph:

In triangle ABC:

Coordinate of C is:

C(-3, 4)

The rule of transformation is given:

(x, y) \rightarrow (x-3, y+1)

We have to find the coordinate of C'.

Apply the transformation on coordinate C:

C(-3, 4) \rightarrow C'(-3-3, 4+1) = C'(-6, 5)

Therefore, the coordinate of C' is (-6, 5)


4 0
3 years ago
10.) Which equation below represents the model? A. m - 11 = 43 B. 11m = 43 C. m + 11 = 43 D. m + 43 = 11.) What is the value of
elixir [45]

Answer:

A

Step-by-step explanation:

m - 11 = 43

3 0
3 years ago
Find direction numbers for the line of intersection of the planes x + y + z = 1 and x + z = 0. (enter your answers as a comma-se
Soloha48 [4]
<1, 1, 1> × <1, 0, 1> = <1, 0, -1>

The cross product of the normals of the planes gives the direction vector of their line of intersection.
7 0
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