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Usimov [2.4K]
3 years ago
6

Determine whether each pair of figures is similar. Justify your answer. DEF is not similar to BAC . Corresponding angles are not

the same. DEF-BAC because the corresponding angles of each triangle are congruent. The ratio of the corresponding sides is 1/2 . DEF-ABC because the corresponding angles of each triangle are congruent. The ratio of the corresponding sides is 2. DEF is not similar to BAC . The ratios of the corresponding sides are not the same.

Mathematics
1 answer:
Margarita [4]3 years ago
7 0

Answer:

Option (2)

Step-by-step explanation:

Two triangle are similar when,

1). Two or more than two angles of the given triangles are equal in measure.

2). Ratio of the corresponding sides are same.

In the triangles ΔDEF and ΔBAC,

m(∠A) = m(∠E) = 58°

m(∠B) = m(∠D) = 53°

m(∠C) = m(∠F) = 69°

And ratio of the corresponding sides,

\frac{\text{EF}}{\text{AC}}=\frac{\text{DF}}{\text{BC}}=\frac{\text{DE}}{\text{AB}}

\frac{2.6}{5.2}=\frac{2.8}{5.6}=\frac{3.1}{6.2}

\frac{1}{2}=\frac{1}{2}=\frac{1}{2}

Therefore, ΔDEF ~ ΔBAC

Option (2) will be the answer.

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the length of the sides of a square are initially 0 cm and increase at a constant rate of 11 cm per second. suppose the function
Likurg_2 [28]

The function of the area of the square is A(t)=121t^{2}

Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area

Lets assume the length of side of square is x

\frac{dx}{dt} = 11 \frac{cm}{sec}

⇒x=11t

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Area of square=(11t)^{2}{as the length of side is 11t}{varies by time}

Area of square=121t^{2}

Therefore,The function of the area of the square is A(t)=121t^{2}

Learn more about The function of the area of the square is A(t)=121t^{2}

Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area

Lets assume the length of side of square is x

\frac{dx}{dt} = 11 \frac{cm}{sec}

⇒x=11t

Area of square=(length of side)^{2}

Area of square=(11t)^{2}{as the length of side is 11t}{varies by time}

Area of square=121t^{2}

Therefore,The function of the area of the square is A(t)=121t^{2}

Learn more about area here:

brainly.com/question/27683633

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3 0
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#6. How do you do it?
bazaltina [42]

Answer:

all work is shown and pictured

6 0
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ArbitrLikvidat [17]

Answer:

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Step-by-step explanation:

First, we subtract 2y on both sides:

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Then, we divide 12 on both sides:

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And we're done ^^ hope this helps!

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Can ya'll help me? tehee :)
monitta
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Hope it helped
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3 years ago
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