X= a number
(2x+4)/3 + (x+2)= 20
Multiply everything by 3 to eliminate the fraction
(3/1)((2x+4)/3) + (3)(x+2)= (3)(20)
2x+4+3x+6= 60
5x+10=60
Subtract 10 from both sides
5x=50
divide both sides by 5
x=10
Check:
Substitute answer in original equation
(2x+4)/3 + (x+2)= 20
(2(10)+4)/3+(10+2)= 20
(20+4)/3+12= 20
24/3+12= 20
8+12= 20
20=20
Hope this helps! :)
Answer:
2x²+2x
Step-by-step explanation:
you have f(x)= x+1 and g(x)= 2x
you must multiply the 2 polynomials
(1x·2x) +( 1·2x)
1·2=2 x^1·x^1=x²
2x²
1·2x=2x
The point is not know I can’t tell u
