A two congruent sides of an isosceles triangle each measure 3b^2 + 2 centimeters the third side measure 4b-5 centimeters what is
the perimeter in centimeters of this triangle????
1 answer:
You need to add (3b^2+2)+(3b^2+2)+(4b-5). This should equal to 6b^2+4b-1.
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pt1= (10,12)
pt2= (10,-8)
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distance = √ (x1 - x2)² + (y2 - y1)²
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=√ (0)² + (-20)²
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=√400
=20 units
Answer:
16
Step-by-step explanation:
I just agree with the other comment
