All categories

3 years ago

What is the slope of the line graph? Enter your answer in the box

Mathematics

2 answers:

uranmaximum [27]3 years ago

6 0

Answer: The slope of the line is $-\frac{1}{3}$ .

Explanation:

From the given graph it is noticed that the line passing through many points.

The coordinates of three given points are (-6,6), (0,4) and (6,2).

If a line passing through two points $(x_1,y_1)$ and $(x_2,y_2)$ , the slope of the lie is defined by,

$m=\frac{y_2-y_1}{x_2-x_1}$

The line passing through two points (0,4) and (6,2). So the slope of the line is,

$m=\frac{2-4}{6-0}$

$m=\frac{-2}{6}$

$m=-\frac{1}{3}$

Therefore, the slope of the line is $-\frac{1}{3}$ .

FrozenT [24]3 years ago

6 0

(-6,6) (6, 2)
slope = (6 - 2)/(-6 -6)
= 4/-12
= -1/3

answer
slope = -1/3

You might be interested in

The numbers 1, 2, 3, 4, and 5 are written on slips of paper, and 2 slips are drawn at random one at a time without replacemen

mamaluj [8]

<h2>Answer:</h2>

(a)

The probability is : 1/2

(b)

The probability is : 1/2

<h2>Step-by-step explanation:</h2>

The numbers 1, 2, 3, 4, and 5 are written on slips of paper, and 2 slips are drawn at random one at a time without replacement.

The total combinations that are possible are:

(1,2) (1,3) (1,4) (1,5)

(2,1) (2,3) (2,4) (2,5)

(3,1) (3,2) (3,4) (3,5)

(4,1) (4,2) (4,3) (4,5)

(5,1) (5,2) (5,3) (5,4)

i.e. the total outcomes are : 20

(a)

Let A denote the event that the first number is 4.

and B denote the event that the sum is: 9.

Let P denote the probability of an event.

We are asked to find:

P(A|B)

We know that it could be calculated by using the formula:

$P(A|B)=\dfrac{P(A\bigcap B)}{P(B)}$

Hence, based on the data we have:

$P(A\bigcap B)=\dfrac{1}{20}$

( Since, out of a total of 20 outcomes there is just one outcome which comes in A∩B and it is: (4,5) )

and

$P(B)=\dfrac{2}{20}$

( since, there are just two outcomes such that the sum is: 9

(4,5) and (5,4) )

Hence, we have:

$P(A|B)=\dfrac{\dfrac{1}{20}}{\dfrac{2}{20}}\\\\i.e.\\\\P(A|B)=\dfrac{1}{2}$

(b)

Let A denote the event that the first number is 3.

and B denote the event that the sum is: 8.

Let P denote the probability of an event.

We are asked to find:

P(A|B)

Hence, based on the data we have:

$P(A\bigcap B)=\dfrac{1}{20}$

( since, the only outcome out of 20 outcomes is: (3,5) )

and

$P(B)=\dfrac{2}{20}$

( since, there are just two outcomes such that the sum is: 8

(3,5) and (5,3) )

Hence, we have:

$P(A|B)=\dfrac{\dfrac{1}{20}}{\dfrac{2}{20}}\\\\i.e.\\\\P(A|B)=\dfrac{1}{2}$

7 0

3 years ago

Evaluate the formula of A=lw, for l=10.8 cm and w=2.5 cm

Setler [38]

Answer:

A = 27 cm²

Step-by-step explanation:

$A = lw\\Where, l=10.8 cm , w = 2.5 cm\\$

Putting in the above formula

A = (10.8)(2.5)

A = 27 cm²

8 0

3 years ago

75 is the median of the data set 68, 67, 75, 73, 72.

Ludmilka [50]

Truee is right you got it dude

4 0

2 years ago

Read 2 more answers

For the function f(x)=x2−24÷3+12<br><br> f(1) <br><br><br> f(0) <br><br><br> f(−1)

LuckyWell [14K]

Put the values of x to the equation of the function.

$f(x)=\dfrac{x^2-24}{3}+12$

$f(1)=\dfrac{1^2-24}{3}+12=\dfrac{1-24}{3}+12=\dfrac{-23}{3}+12=-7\dfrac{2}{3}+12=4\dfrac{1}{3}\\\\f(0)=\dfrac{0^2-24}{3}+12=\dfrac{-24}{3}+12=-8+12=4\\\\f(-1)=\dfrac{(-1)^2-24}{3}+12=\dfrac{1-24}{3}+12=\dfrac{-23}{3}+12=-7\dfrac{2}{3}+12=4\dfrac{1}{3}$

3 0

3 years ago

Please help me with question #6!!!

Bumek [7]

Previous balance:

+ $481,47→ 11/30
- $300,00 → 11/02
- $68,99 → 11 / 10
- $45,00 → 11/15
- $72,75 → 11/17
----------------------------
+ $481,47 - $113,26 =
+ $368,21

new balance:

+ $481,47→ 11/30
- $300,00 → 11/02
- $ $\diagup\!\!\!\! 68,\diagup\!\!\!\!99$ → 11 / 10 for -$58,99
- $45,00 → 11/15
- $ $\diagup\!\!\!\! 72,\diagup\!\!\!\!75$ → 11/17 for $ 0
-------------------------------------------------------------------------------------
+ $481,47 - $196,01 =
+$285,46

Answer:
$\boxed{+285,46}$

4 0

3 years ago