The example on direct variation is illustrated below based on the information given.
<h3>How to illustrate the direct variation?</h3>
An example will be:
When x = 2, y = 10. Find the value of y when x is 6.
In this case, this will be calculated thus:
y = kx
10 = 2k
k = 10/2
k = 5
Since y = kx.
y = 5 × 6
y = 30
The value of y is 30.
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Answer:
y=-8/5x+77/5
Step-by-step explanation:
The equation of line that passes through the points (4, 9) and (9, 1) is y=-8/5x+77/5. Hope it helps!
Answer:
The area of a label is 
Step-by-step explanation:
we know that
The lateral area of a cylinder (label of the can) is equal to
we have that
A can is 4 inches wide
so
The diameter of the can is 4 inches
----> the radius is half the diameter
----> height of the label
substitute in the formula
1/4x -2 = -6 + 5/12x
3x - 24 = -72 +5x
3x -5x = -72 +24
-2x = -48
x = 24
Answer: Choice A) A true null hypothesis is rejected
In other words, if the reality is that the null is true but your research says otherwise, then you've committed a type i error.
A type ii error is when you fail to reject the null (basically "accepting" the null) while in reality the alternative is the true hypothesis.
