Answer:
∠RPQ = 27
Step-by-step explanation:
In ΔSRQ,
∠R = 90
∠SQR = 36°
∠R + ∠SQR + ∠RSQ = 180 {Angle sum property of triangle}
90 + 36 + ∠RSQ = 180
126 + ∠RSQ = 180
∠RSQ = 180 - 126
∠RSQ = 54°
∠PSQ +∠RSQ = 180 {Linear pair}
∠PSQ + 54 = 180
∠PSQ = 180 - 54
∠PSQ = 126
In ΔPSQ,
SQ = PS ,
So, ∠SQP = ∠SPQ {Angles opposite to equal sides are equal}
∠SQP = ∠SPQ =x
∠PSQ + x +x = 180 {Angle sum property of triangle}
126 + 2x = 180
2x = 180 - 126
2x = 54
x = 54/2
x = 27
∠RPQ = 27°
The answer would be 0.1215
I'd suggest using a calculator!<span />
The biggest is hm that is because it matters
Answer:
EG = 41
Step-by-step explanation:
the 2 base angles are congruent then the triangle is isosceles with the 2 legs being congruent , that is
7x + 9 = 5x + 23 ( subtract 5x from both sides )
2x + 9 = 23 ( subtract 9 from both sides )
2x = 14 ( divide both sides by 2 )
x = 7
then
EG = 6x - 1 = 6(7) - 1 = 42 - 1 = 41
