Answer:
answer c is 28 cubes
Step-by-step explanation:
We have that
smaller figure
ha=8.7
ra=1.6
larger figure
hb=10.44
rb=1.92
ha/hb=8.7/10.44----> 0.83
ra/rb=1.6/1.92-------> 0.83
ratio smaller figure to the larger figure
1.6/1.92-------> divided by 1.6 both members[1.6/1.6]/[1.92/1.6]-------> 1/1.2
the ratio ha/hb is equal to the ratio ra/rb
so
the smaller figure and the larger figure are similar
and
the ratio smaller figure to the larger figure is equal to----> 1/1.2
the answer is
the option yes 1/1.2
Answer:
Step-by-step explanation:
My approach was to draw out the probabilities, since we have 3 children, and we are looking for 2 boys and 1 girl, the probabilities can be Boy-Boy-Girl, Boy-Girl-Boy, and Girl-Boy-Boy. So a 2/3 chance if you think about it, your answer 2/3 can't be correct. If we assume that boys and girls are born with equal probability, then the probability to have two girls (and one boy) should be the same as the probability to have two boys and one girl. So you would have two cases with probability 2/3, giving an impossible 4/3 probability for both cases. Also, your list "Boy-Boy-Girl, Boy-Girl-Boy, and Girl-Boy-Boy" seems strange. All of those are 2 boys and 1 girl, so based on that list, you should get a 100 percent chance. But what about Boy-Girl-Girl, or Girl-Girl-Girl? You get 2/3 if you assume that adjacencies in the (ordered) list are important, i.e., "2 boys and a girl" means that the girl was not born between the boys.
Answer:
2.50*10 350+d
Step-by-step explanation:
- thats the answer up below
