Since both arrays are already sorted, that means that the first int of one of the arrays will be smaller than all the ints that come after it in the same array. We also know that if the first int of arr1 is smaller than the first int of arr2, then by the same logic, the first int of arr1 is smaller than all the ints in arr2 since arr2 is also sorted.
public static int[] merge(int[] arr1, int[] arr2) {
int i = 0; //current index of arr1
int j = 0; //current index of arr2
int[] result = new int[arr1.length+arr2.length]
while(i < arr1.length && j < arr2.length) {
result[i+j] = Math.min(arr1[i], arr2[j]);
if(arr1[i] < arr2[j]) {
i++;
} else {
j++;
}
}
boolean isArr1 = i+1 < arr1.length;
for(int index = isArr1 ? i : j; index < isArr1 ? arr1.length : arr2.length; index++) {
result[i+j+index] = isArr1 ? arr1[index] : arr2[index]
}
return result;
}
So this implementation is kind of confusing, but it's the first way I thought to do it so I ran with it. There is probably an easier way, but that's the beauty of programming.
A quick explanation:
We first loop through the arrays comparing the first elements of each array, adding whichever is the smallest to the result array. Each time we do so, we increment the index value (i or j) for the array that had the smaller number. Now the next time we are comparing the NEXT element in that array to the PREVIOUS element of the other array. We do this until we reach the end of either arr1 or arr2 so that we don't get an out of bounds exception.
The second step in our method is to tack on the remaining integers to the resulting array. We need to do this because when we reach the end of one array, there will still be at least one more integer in the other array. The boolean isArr1 is telling us whether arr1 is the array with leftovers. If so, we loop through the remaining indices of arr1 and add them to the result. Otherwise, we do the same for arr2. All of this is done using ternary operations to determine which array to use, but if we wanted to we could split the code into two for loops using an if statement.
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The above statement is FALSE.
A photo's color intensity can be modified by changing the brightness and CONTRAST.
There are four common image controls that makes an image easy to view. These controls are brightness, contrast, saturation, and sharpness.
Brightness control simply brightens the whole image from the shadows to the highlights equally.
Contrast control is the separation between the darkest and brightest areas of the image.
Saturation control is the separation of colors in the image.
Sharpness control is defined as the edge contrast, meaning the edges in the image are the ones being contrasted.
Answer: True
Explanation:
Virtual memory is the secondary storage memory and this type of memory are addressed as main part of the memory.
When the virtual memory copying in the physical memory then, at that time the operating system divide the memory into the file page with the address and definite size number. Then, the each page are store in a disk.
When this page are required then, the operating system copy from disk to main memory and then, the virtual address are converted into the real address.
Answer: C 475
Explanation: These choices are A. 375, B. 276, and D. 575. so that wolde mean it would be C 475.
